Only one positive prime number has a 5 in the ones digit. That prime number is 5. All other numbers with a 5 in the ones digit are composite because they will be divisible by 5.
The "ones" place is always the last digit in any number so multiples of 5 always have either 5 or 0 (zero) in the "ones" digit position.
15
The ones digit in the product from multiplying the 305 prime numbers less than 2012 is 0 because the ones digit becomes 0 after 2 and 5 have been multiplied and remains unchanged after more prime numbers are multiplied.
To find if a number is divisible by 5, the digit in the ones place has to be 0 or 5.
The answer depends on what the tens digit is greater than, and what the ones digit does then.
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
To determine the number of 3-digit numbers that are multiples of 5, we need to find the first and last 3-digit multiples of 5. The first 3-digit multiple of 5 is 100, and the last 3-digit multiple of 5 is 995. To find the total number of such multiples, we can use the formula (Last - First) / 5 + 1 = (995 - 100) / 5 + 1 = 180. Therefore, there are 180 3-digit numbers that are multiples of 5.
Since cents are only in whole numbers, you look at the digit directly to the right of the ones digit. In this case, it is a 7. Since that is 5 or greater, the ones digit is rounded up. The answer is 16 cents.
875
-3
In the number 15, the digit 5 holds a place value of 5 units. This means that the digit 5 represents 5 ones in the number 15. The value of the digit 5 in this case is 5.