Multiply 630 by .25: 630 * .25 = 157.5
There are infinitely many number pairs: Select any number, X, greater than sqrt(630) = 25.1 Let Y = 630/X Then X*Y = X*(630/X) = 630 Since there are infinitely many numbers greater than 25.1 and X can be any one of them, there are infinitely many possible answers.
18 and 630
Find the numbers that include others in their prime factorization: 7, 9, and 10 Multiply them: 630
630 315,2 105,3,2 35,3,3,2 7,5,3,3,2
3150
630
Multiply 630 by .25: 630 * .25 = 157.5
There are infinitely many number pairs: Select any number, X, greater than sqrt(630) = 25.1 Let Y = 630/X Then X*Y = X*(630/X) = 630 Since there are infinitely many numbers greater than 25.1 and X can be any one of them, there are infinitely many possible answers.
Multiply 63 by 10 is 630
18 and 630
Multiply it by 100 and so it is 630%
Find the numbers that include others in their prime factorization: 7, 9, and 10 Multiply them: 630
The highest common factor of the numbers 490 and 630 is 70.
The least common multiple of the numbers 105 and 90 is 630.
It is: 2*3*3*5*7 = 630
630 315,2 105,3,2 35,3,3,2 7,5,3,3,2