the diagonals of a rhombus measure 16 cm and 30 cm.find its perimeter.
It is: 0.5*10*12 = 60 square m
Area of the rhombus: 0.5*8*10 = 40 square feet
It is a kite or a rhombus both of which have unequal diagonals that are perpendicular to each other creating right angles.
is the perimeter of the triangle whose sides measure 7.5 7.1 and 8.1
The diagonals of a rhombus intersect at 90 degrees therefore it has 4 right angle triangles with sides of 5 and 6 respectively with the hypotenuse being a side of the rhombus. So using Pythagoras' theorem: 52+62 = 61 and the square root of this is the length of each side of the rhombus which is approximately 7.81 units of measurement
It is: 0.5*10*12 = 60 square m
parallelogram, rhombus, trapezoid and a kite
It is a rhombus whose diagonals are perpendicular and meeting each other at right angles.
0.790 radians (45.2 degrees) and 2.352 radians (134.8 degrees).
Area of the rhombus: 0.5*7.5*10 = 37.5 square cm Perimeter using Pythagoras: 4*square root of (3.75^2 plus 5^2) = 25 cm
How about a rhombus or a kite
Area of the rhombus: 0.5*8*10 = 40 square feet
123
A quadrilateral whose diagonals bisect each other at right angles is a rhombus. each other at right angles at M. So AB = AD and by the first test above ABCD is a rhombus. 'If the diagonals of a parallelogram are perpendicular, then it is a rhombus
The diagonals of a rhombus (not rombhus) bisect one another at right angles. The sides of the rhombus form the hypotenuses of triangles whose other sides are half the diagonals. So use Pythagoras.
A square, rhombus and a kite are examples of shapes whose diagonals bisect each other at 90 degrees
It is a kite or a rhombus both of which have unequal diagonals that are perpendicular to each other creating right angles.