15, 30, 45 and so on.
the multiples of 3 are........0,3,6,9,12,15,18,21,24,27.... and more
they r 90, 180 and 270
The first 6 multiples of 5 are: 5, 10, 15, 20, 25, and 30.
Any multiple of 12.
Itself and any of its multiples
For an Arithmetic Progression, Sum = 15[a + 7d].{a = first term and d = common difference} For a Geometric Progression, Sum = a[1-r^15]/(r-1).{r = common ratio }.
There is only one greatest common factor.For 45 and 75 it is:75 / 45 = 1 r 3045 / 30 = 1 r 1530 / 15 = 2 r 0GCF of 45 and 75 is 15.Other common factors of 45 and 75: 1, 3, 5.
Yes, that is a very common change
175 / 80 = 2 r 15 80 / 15 = 3 r 5 15 / 5 = 3 r 0 gcf of 80 and 175 is 5.
To find the number of ways to select 3 flavors from 15, you can use the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 15 ) and ( r = 3 ). Therefore, the calculation is ( C(15, 3) = \frac{15!}{3!(15-3)!} = \frac{15 \times 14 \times 13}{3 \times 2 \times 1} = 455 ). Thus, there are 455 ways to select 3 flavors of juice.
r=y
15 1*15 3*5 factor:1,3,5,15