Using Pythagoras' theorem: 425
The diagonal measurement of an 8 ft square is: 11.31 feet.
If the side of the square is s inches, then the diagonal is s*sqrt(2) So s*sqrt(2) = 250 s = 250/sqrt(2) = 176.78 inches.
The diagonal length is about 20.59
The diagonal is 20.
The diagonal measurement for 36 feet by 36 feet is 50.91 feet.
A 12" x 12" square has a diagonal measurement of: 16.97 inches.
Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 12 × √2 ≈ 17.0 units
64'1"x107'1"
the diagonal
67'1"
To find the diagonal measurement of a rectangle, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement of a 40' x 50' rectangle can be calculated as follows: diagonal = √(40^2 + 50^2) = √(1600 + 2500) = √4100 ≈ 64.03 feet.
Diagonal = 36.9 feet