The diagonal measurement of an 8 ft square is: 11.31 feet.
Chat with our AI personalities
I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
the square root of 128 or 8 times the square root of 2.
Oh, dude, you're hitting me with the math questions now? Okay, okay, so if you wanna find the diagonal of an 8 ft by 12 ft rectangle, you can use the Pythagorean theorem. It's like a^2 + b^2 = c^2, so in this case, 8^2 + 12^2 = c^2. Just crunch those numbers and you'll get the diagonal length. Easy peasy, right?
8*sqrt(2) The diagonal of the square would be the hypotenuse of the right triangle formed by two of the sides of the square.
Well, isn't that just a happy little question! When you have a square that's 8 feet by 8 feet, you can use the Pythagorean theorem to find the diagonal. Simply square the length of one side (8²), multiply it by 2, and then take the square root of that sum. So, the diagonal dimension of your square would be about 11.31 feet. Just imagine that diagonal stretching across your canvas, bringing a sense of balance and harmony to your artwork.