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Q: What two factors of 64 have a sum of 19?

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It is 126.

83 is the answer. Just add! (:

To tackle this question, you first need to break the number down into its prime factors. In this case we have 64 = 2x2x2x2x2x2 To find the greater factors, you need to multiply any combination of these. That gives us the factors as 2, 4, 8, 16, 32 and 64 Adding these up for the sum gives us 126 Thus the sum of all even factors of 64 is 126.

1 + 64 + 2 + 32 + 4 + 16 + 8 = 127

2^64 =1.8446744e+19

there is no, because in order for it to have one, one of its factors has to be odd.

64 + 16

xy = 64 x + y = 16 y = 16-x x(16-x) = 64 16x -x^2 -64 = 0 x^2 -16x + 64 = 0 (x-8)(x-8) =0 both factors = 8

64

36 and 64

64

The numbers are 98 and 64

64 and 36.

How about: 36+64 = 100

64.

45 and 19 are the numbers.

The factors of 64 are: 1, 2, 4, 8, 16, 32, 64The factors of 76 are: 1, 2, 4, 19, 38, 76

Abundant, deficient and perfect numbers are determined by the sum of the proper divisors (or factors) of a number, which excludes the number itself. The factors of 76 are : 1,2,4,19,38,76 . . . after excluding the number itself the sum of the proper divisors is :- 1+2+4+19+38= 64 Deficient numbers occur when the sum of the proper divisors is less than the number itself. As 64 is less that 76 then it is deficient.

64 = 8 x 8

The sum of the prime numbers 11 and 53 equals 64.

They are 36 and 64

They are 36 and 64

They are: 36 and 64

64

61 and 3