k = 5
4
false
x1 + x2 / y1 +y2
You wouldn't normally list it in a factor tree, because it's not technically a prime number, and besides if you did, you could keep on adding x1 x1 x1 x1 forever and not change the value.That being said, if you wanted to show the factorization of a prime number, you'd most likely write it as (for example) 709 x 1, just to show that nothing else divides evenly into 709.
shut up and do your hw
it equals x1 it equals x1
4
false
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-1 plus or minus the square root of 265) divided by 12 x = 1.2732350496749756 x = -1.439901716341642
3
2x2+7/x1
The answer depends on absolute deviation from what: the mean, median or some other measure. Suppose you have n observations, x1, x2, ... xn and you wish to calculate the sum of the absolute deviation of these observations from some fixed number c. The deviation of x1 from c is (x1 - c). The absolute deviation of x1 from c is |x1 - c|. This is the non-negative value of (x1 - c). That is, if (x1 - c) ≤ 0 then |x1 - c| = (x1 - c) while if (x1 - c) < 0 then |(x1 - c)| = - (x1 - c). Then the sum of absolute deviations is the above values, summed over x1, x2, ... xn.
x1 + x2 / y1 +y2
You wouldn't normally list it in a factor tree, because it's not technically a prime number, and besides if you did, you could keep on adding x1 x1 x1 x1 forever and not change the value.That being said, if you wanted to show the factorization of a prime number, you'd most likely write it as (for example) 709 x 1, just to show that nothing else divides evenly into 709.
It is false-apex
The answer is: X1 = 2 X2 = -7
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