Length = 20 mBreadth = 19 mPerimeter = 2(Length + Breadth) = 2(20 + 19) = 2 * 39 = 78 mArea = Length * Breadth = 20 * 19 = 380 m2
Length = 38 feet Width = 19 feet Check: 2*(38+19) = 114 feet
A rectangle with a perimeter of 48 and 1 side equal to 5 would have its other sides lengths of 5, 19, 19. Such a rectangle would have an area of 95 sq/m. Your question is somewhat strange, as the "length" of a rectangle generally refers to the longer side - in this case the length would be 19 and the width 5.
If the length of a rectangle is 33, and the width is 19, the perimeter would be 104. === === P = 2 (l+w) P = 2 (33+19) P = 2 (52) P = 104
76 Area = 361 = (side length)^2. This tells us that the length of a side is 19. Perimeter = 4*(side length) = 4*19=76.
It works out as 19 m in length and 13 m in width.
If the perimeter is 76, then the length of a side is (76/4) = 19 mm.The area is the square of the length of a side = (19)2 = 361 mm2
52 miles.
44m
It is 48.
Length of one side = 114/6 inches = 19 inches
A heptagon has 7 sides. A regular heptagon has all sides the same length, in this case 19 units long. Thus the perimeter = 7 x 19 units = 133 units.