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What is the perimeter of a rectangle with the length of 19 m and width of 3 m?
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∙ 7y ago
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Samrat Rathore
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∙ 7y ago44
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The width of a rectangle is 12 cm shorter than the length The perimeter is at least 52 cm What are the smallest possible dimensions of the rectangle?
7 x 19 cm
When the perimeter of a rectangle is 128m the lengeth is 7m than twice the widethfind the length and the wideth?
Let the length be 2x+7 and the width be x: 2(length+width) = perimeter 2(2x+7+x) = 128 4x+14+2x = 128 4x+2x = 128-14 6x = 114 x = 19 Therefore: length = 45m and width = 19m Check: 45+45+19+19 = 128m
What is the perimeter of a 9.5 inch by 11.5 inch rectangle?
The perimeter of a 9.5 x 11.5 inch rectangle is 42 inches. To find the perimeter of a rectangle we use the formula Length * 2 + Width * 2 That gives us the following expression. 9.5 * 2 + 11.5 * 2 19 + 23 42
The width of a rectangle is 12 cm shorter than the length The perimeter is 52 cm What are the demensions of the rectangle?
Let the width be x-12 and the length be x: 2(x-12+x) = 52 2x-24+2x = 52 2x+2x = 52+24 4x = 76 Divide both sides by 4 to determine the value of x: x = 19 Therefore: width = 7 cm and the length = 19 cm
If the Perimeter of the rectangle is 38 inches the length is 3 inches more find the width?
The formula for the perimeter of a rectangle is P=2(l + w). You know that the length is 3" more than the width. Hence you could substitute x for the width and x+3 for the length and use the formula to solve for the width: P = 2(l + w) 38 = 2(x + 3 + x) 38 = 4x + 6 32 = 4x 8 = x Hence, the width is 8" and the length is 11" Proof: P = 2(11 + 8) P = 2(19) P = 38
What is the length of a rectangular lot with a perimeter of 72 m if the length is 8 m more than the width?
The length of the rectangle is 27 meters and the width is 19 meters.
What would be the perimeter of 28 in length and 19 in wide?
If we're talking a rectangle here, all you need to do is add length and width then double your answer...
What is the area of a rectangle with a perimeter of 48 and a length of 5?
A rectangle with a perimeter of 48 and 1 side equal to 5 would have its other sides lengths of 5, 19, 19. Such a rectangle would have an area of 95 sq/m. Your question is somewhat strange, as the "length" of a rectangle generally refers to the longer side - in this case the length would be 19 and the width 5.
The perimeter of a rectangle is 86 cm the length is 19 cm greater than the width. how i can find the length and the width?
2x+2y=86 y=19 2x+2(19)=86 2x=48 x=24 length=19 (given in question) width= 24 (solved above)
The width of a rectangle is 12 cm shorter than the length The perimeter is at least 52 cm What are the smallest possible dimensions of the rectangle?
7 x 19 cm
What is the perimeter of a square if I have 33 and 19?
If the length of a rectangle is 33, and the width is 19, the perimeter would be 104. === === P = 2 (l+w) P = 2 (33+19) P = 2 (52) P = 104
When the perimeter of a rectangle is 128m the lengeth is 7m than twice the widethfind the length and the wideth?
Let the length be 2x+7 and the width be x: 2(length+width) = perimeter 2(2x+7+x) = 128 4x+14+2x = 128 4x+2x = 128-14 6x = 114 x = 19 Therefore: length = 45m and width = 19m Check: 45+45+19+19 = 128m
What is the perimeter of a 9.5 inch by 11.5 inch rectangle?
The perimeter of a 9.5 x 11.5 inch rectangle is 42 inches. To find the perimeter of a rectangle we use the formula Length * 2 + Width * 2 That gives us the following expression. 9.5 * 2 + 11.5 * 2 19 + 23 42
What is the width of a rectangle that is 228 square feet if the length is 12?
The width is 228/12 = 19 feet
The width of a rectangle is 12 cm shorter than the length The perimeter is 52 cm What are the demensions of the rectangle?
Let the width be x-12 and the length be x: 2(x-12+x) = 52 2x-24+2x = 52 2x+2x = 52+24 4x = 76 Divide both sides by 4 to determine the value of x: x = 19 Therefore: width = 7 cm and the length = 19 cm
What is the area of a rectangle whose length is 8 cm and whose width is 19 cm?
The area of rectangle is : 152.0
If the Perimeter of the rectangle is 38 inches the length is 3 inches more find the width?
The formula for the perimeter of a rectangle is P=2(l + w). You know that the length is 3" more than the width. Hence you could substitute x for the width and x+3 for the length and use the formula to solve for the width: P = 2(l + w) 38 = 2(x + 3 + x) 38 = 4x + 6 32 = 4x 8 = x Hence, the width is 8" and the length is 11" Proof: P = 2(11 + 8) P = 2(19) P = 38
