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Double its height or increase its radius by a factor of sqrt(2) = 1.4142 (approx) or some combination of changes to he height and radius.
it will increase more if you double the radius because the dimensions multiply and the curved surface has less area to cover as its height decreases and width increases
Your diameter is double the radius. So the diameter is 6
It is a modified version of the Pythagorean theorem instead of a^2+b^2=c^2 it is h^2+r^2= l^2 where h is height r is radius and l is slant height This is the same thing for slant height for pyramid except instead of radius, it is 1/2 the base
if its a cone: volume= (1/3) base* height or volume= (1/3) pi *radius*radius[r squared]* height
Double its height or increase its radius by a factor of sqrt(2) = 1.4142 (approx) or some combination of changes to he height and radius.
it will increase more if you double the radius because the dimensions multiply and the curved surface has less area to cover as its height decreases and width increases
Since the volume of a cone is proportional to the square of the radius (look at the formula), double the radius would mean four times the volume.
If you notice the formulas you will see that the height and the radius are multiplied by 2, both of them. When you multiplied these together it will be like multiplying 2x2.
If you double the diameter, or the radius, then the perimeter will also double.
Your diameter is double the radius. So the diameter is 6
the volume changes as radius squared and linear with height, so tripling radius and double of height gives 3 x 3 x 2 = 18 times more volume
It is a modified version of the Pythagorean theorem instead of a^2+b^2=c^2 it is h^2+r^2= l^2 where h is height r is radius and l is slant height This is the same thing for slant height for pyramid except instead of radius, it is 1/2 the base
#include<iostream> struct shape { virtual double area () const = 0; }; struct triangle : shape { triangle (double b, double h): base (b), height (h) {} double base, height; double area () const override { return base * height / 2; } }; struct circle : shape { circle (double r): radius (r) {} double radius; double area () const override { return 4 * atan(1) * radius * radius; } }; struct rectangle : shape { rectangle (double w, double h): width (w), height (h) {} double width, height; double area () const override { return width * height; } }; int main() { triangle t (10, 5); std::cout << "triangle with base " << t.base << " and height " << t.height << " has area " << t.area() << std::endl; circle c (5); std::cout << "circle with radius " << c.radius << " has area " << c.area() << std::endl; rectangle r (10, 5); std::cout << "rectangle with width " << r.width << " and height " << r.height << " has area " << r.area() << std::endl; }
#include #include #define pi=3.141593 void main() { float r,h,a; clrscr(); printf("Enter the radius:\t"); scanf("%f",&r); printf("\nEnter the hight:\t"); scanf("%f",&h); a=pi*r*r*h; printf("\n The area of cylinder is: %f",a); getch(); }
Yes its height is the same as its radius
The radius of a cylinder is independent of its height.