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if you are integrating with respect to x, the indefinite integral of 1 is just x

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โˆ™ 2009-11-30 13:11:02
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Q: What you the integral of 1?
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Related questions

What is the integral of 1 divided by 2x squared?

0.5


Integral of 1 plus x2?

The integral of 1 + x2 is x + 1/3 x3 + C.


What is the double integral of 2x?

The integral of a single term of a polynomial, in the form of AxN is (A/N+1) x (N+1). The first integral of 2x is x2 + C. The second integral of 2x is the first integral of x2 + C, which is 1/3x3 + Cx + C.


What is the definite integral of 1 divided by x squared?

There can be no definite integral because the limits of integration are not specified. The indefinite integral of 1/x2 is -1/x + C


How do you evaluate definite integrals?

In order to evaluate a definite integral first find the indefinite integral. Then subtract the integral evaluated at the bottom number (usually the left endpoint) from the integral evaluated at the top number (usually the right endpoint). For example, if I wanted the integral of x from 1 to 2 (written with 1 on the bottom and 2 on the top) I would first evaluate the integral: the integral of x is (x^2)/2 Then I would subtract the integral evaluated at 1 from the integral evaluated at 2: (2^2)/2-(1^2)/2 = 2-1/2 =3/2.


Integral of -x 2?

The integral of -x2 is -1/3 x3 .


What is the integral of arcsinxdx?

The integral of arcsin(x) dx is x arcsin(x) + (1-x2)1/2 + C.


What is the integral of 1 divided by x squared?

The indefinite integral of (1/x^2)*dx is -1/x+C.


What is the integral of 2-x?

The integral of 2-x = 2x - (1/2)x2 + C.


How would you solve the integral of 1 plus tan2x plus tan squared 2x?

Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C


What is the antiderivative of x to the 1?

By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2


What is the integral of x divided by x plus 1?

x/(x+1) = 1 - 1/(x + 1), so the antiderivative (or indefinite integral) is x + ln |x + 1| + C,


Integral of 1 divided by sinx cosx?

Integral of [1/(sin x cos x) dx] (substitute sin2 x + cos2 x for 1)= Integral of [(sin2 x + cos2 x)/(sin x cos x) dx]= Integral of [sin2 x/(sin x cos x) dx] + Integral of [cos2 x/(sin x cos x) dx]= Integral of (sin x/cos x dx) + Integral of (cos x/sin x dx)= Integral of tan x dx + Integral of cot x dx= ln |sec x| + ln |sin x| + C


What is the integral of the square root of x minus 1 squared?

the integral of the square-root of (x-1)2 = x2/2 - x + C


What is the answer to 1 to the 2nd power?

1 to any integral power is 1.


What is the integral of the e?

x=1


What is integral of sin3ycos5y?

-1/15sin5ycos3y


What is non integral numbers?

non integral is type of numbers behaviour: i can say that set of numbers without any "holes inside" are integral and set of numbers with "holes inside are non integral. example : integral group "1..100" non integral group "1,4,8,67"


Integral of xlnxdx?

integration by parts. Let u=lnx, dv=xdx-->du=(1/x)dx, v=.5x^2. Integral of (xlnxdx)=lnx*.5x^2-integral of .5x^2(1/x)dx=lnx*.5x^2-integral of .5xdx=lnx*.5x^2-(1/6)x^3. That's it.


What is the integral of cosine cubed?

The integral of cosine cubed is sinx- 1/3 sin cubed x + c


What is the integral of 1-x-xx 2 1?

x


Which is harder calculus 1 or differential and integral calculus?

Just about all of calculus is based on differential and integral calculus, including Calculus 1! However, Calculus 1 is more likely to cover differential calculus, with integral calculus soon after. So there really isn't a right answer for this question.


What are the different examples of integral exponents?

... -3, -2, -1, 0, 1, 2, 3, ...In summary, any integer that you use as an exponent is an "integral exponent".... -3, -2, -1, 0, 1, 2, 3, ...In summary, any integer that you use as an exponent is an "integral exponent".... -3, -2, -1, 0, 1, 2, 3, ...In summary, any integer that you use as an exponent is an "integral exponent".... -3, -2, -1, 0, 1, 2, 3, ...In summary, any integer that you use as an exponent is an "integral exponent".


Integration of tan pow4x?

integral of (tanx)^4 (tanx)^4 = (tanx)^2 (tanx)^2 =(sec^2 x - 1)(tan^2 x) =(sec^2 x)(tan^2 x) - tan^2 x = integral of sec^2 x tan^2 x dx - integral of tan^2 x dx First, integral of sec^2 x tan^2 x dx Let u = tanx because that would make du = sec^2 x dx so then we have integral of u^2 du which is (1/3)u^3 substituting back in tanx we get (1/3)tan^3 x Next, integral of tan^2 x tan^2 x = sec^2 x -1 integral of sec^2 x - 1 = integral of sec^2 x dx - integral 1 dx = tanx - x so putting it all together we have integral of tan^4 x dx = (1/3)tan^3 x - tanx + x + C


What is the integral of 3 over 3x?

The 3s would cancel and it would become the integral of 1/x which is ln x.