n+n+1+n+2=9000
3n+2=9000
3n=9000-2
3n=8997
n=8997/3
n=2999
n+1=3000
n+2=3001
First of all, you need to be more specific. It's three consecutive integers. And they are 2,999, 3,000, and 3,001
Sum of numbers in a nth row can be determined using the formula 2^n. For the 100th row, the sum of numbers is found to be 2^100=1.2676506x10^30.
The sum of the numbers in each row of Pascal's triangle is twice the sum of the previous row. Perhaps you can work it out from there. (Basically, you should use powers of 2.)
8,000. each row's sum is the row # cubed. so the 20th row is 20*20*20 = 8000
The sum of the numbers on the fifteenth row of Pascal's triangle is 215 = 32768.
the horizontal sums doubles each time the sum of row 1 = 1 row 2= 2 row 3 = 4 row 4 = 8 row 5 = 16 etc etc.......... the horizontal sums doubles each time the sum of row 1 = 1 row 2= 2 row 3 = 4 row 4 = 8 row 5 = 16 etc etc..........
16020
The sum of the numbers in the nth row of Pascal's triangle is equal to 2^n. Therefore, the sum of the numbers in the 100th row of Pascal's triangle would be 2^100. This formula is derived from the properties of Pascal's triangle, where each number is a combination of the two numbers above it.
When estimating the sum of 48765 and 9221, you can round each number to the nearest thousand. 48765 rounds to 49000, and 9221 rounds to 9000. Adding these rounded numbers gives you an estimated sum of 58000. To estimate the difference, you can round 48765 to 49000 and 9221 to 9000. Subtracting these rounded numbers gives you an estimated difference of 4000.
64
=SUM(A1:A17) for example
18 + 19 + 20 = 57