If a monotone sequence An is convergent, then a limit exists for it. On the other hand, if the sequence is divergent, then a limit does not exist.
The limit is the Golden ratio which is 0.5[1 + sqrt(5)]
No, such a sequence is not posible.
Students surely can recognize the number that is the limit of this sequence.
A binary sequence is one in which only two different values are allowed. In computers, 1 and 0 are the conventional ones. So 10100110001 is a binary sequence. The sex of children born to a given set of parents could be b,g,g,b. This is a binary sequence. There is no conceptual limit to the length of a binary sequence.
Wrong answer above. A limit is not the same thing as a limit point. A limit of a sequence is a limit point but not vice versa. Every bounded sequence does have at least one limit point. This is one of the versions of the Bolzano-Weierstrass theorem for sequences. The sequence {(-1)^n} actually has two limit points, -1 and 1, but no limit.
The reason main sequence has a limit at the lower end is because of temperature and pressure. The lower limit exists in order to exclude stellar objects that are not able to sustain hydrogen fusion.
The limit does not exist.
To the best of my knowledge, a random sequence limit imposes restrictions on random number generation. For example, one may want to generate random numbers such that any number does not occur consecutively three times. Another definition of a random sequence limit is the number that a sequence of random measurements of some property converge to as the number of measurements increase.
the limit does not exist
A sequence is a function ! whose domian is the set of natural numbers
As x goes to infinity, the limit does not exist.