Q: What is x2 plus x-5 equals 0?

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x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.

-2

no

x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0

x2 + 36x = 0 x2 = -36x x = -36

No.

168

X=i root3

(x+1)(x+4) = 0

x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0

x = -3.27 or -6.73

x2 + 49 = 0 ∴ x2 = -49 ∴ x = 7i

(2-r)e-rr

Yes

x2 + 13x + 36 = 0 so (x+4)(x+9) = 0 so that x = -4 or x = -9

x5 - 2x4 - 24x3 = 0 x3(x2 - 2x - 24) = 0 x3(x2 + 4x - 6x - 24) = 0 x3(x - 6)(x + 4) = 0 x = {-4, 0, 6}

2x^2 + 8x + 3 = 0

If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)

(x + 3)(x + 4)

x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}

3

It is -13.

The discriminant is -11.

x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6

x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0

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