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They touch each other at (0, 100) on the x and y axis.

Q: Where do the parabolas of y equals x squared plus 20x plus 100 and y equals x squared minus 20x plus 100 meet on the x and y axis?

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The form is not specified in the question so it is hard to tell. But two parabolas with different vertices can certainly have the same axis of symmetry.

(X-3)(X-3) Foil that and you will see tha X = 3. This is a parabola that touches the X axis at X = 3.

Draw the graph of negative X squared plus 5 minus X cubed and find the values of x where it intersects the x axis.

Yes, it crosses at (0.23,0) and (1.43,0).

y=6x² is already solved. the parabola will touch the x-axis at x=0.

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the x-axis... obviously! the x-axis... obviously!

The form is not specified in the question so it is hard to tell. But two parabolas with different vertices can certainly have the same axis of symmetry.

(X-3)(X-3) Foil that and you will see tha X = 3. This is a parabola that touches the X axis at X = 3.

Draw the graph of negative X squared plus 5 minus X cubed and find the values of x where it intersects the x axis.

its a simple parobola symmetric about y axis, having its vertex at (0,-4). we can make its graph by changing its equation in standard form so that we can get its different standard points like vertex, focus, etc.

Yes, it crosses at (0.23,0) and (1.43,0).

y=6x² is already solved. the parabola will touch the x-axis at x=0.

It is x^2 - 5 which, if plotted on the x-y plane will be a parabola which is symmetric about the y axis and has its apex at (0, -5) .

Cuts through the y axis at: (0, -12) Cuts through the x axis at: (-3, 0) and (4, 0)

It is a straight line. The line intersects the y-axis at (0, -4); the x-axis at (6, 0) and has a gradient (slope) of 2/3

It is 8*sqrt(2)/3 = 3.7712 approx.

The solution comprises every point on a parabola which is symmetric about the y axis and has its apex at (0,1).