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The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).

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โˆ™ 2010-06-28 01:12:24
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Q: Where is the center of the circle given by the equation x - 3 squared plus y plus 2 squared equals 9?
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Related questions

Where is the center of the circle given by the equation x 4 squared y - 3 squared equals 4?

(-4,3)


Where is the center of the circle given by the equation x plus 4 squared plus y plus 6 squared equals 49?

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How do you graph the equation x squared plus y squared equals 16?

You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)


Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 squared equals 25?

The centre is (-5, 3)


Where is the center of the circle given by the equation x plus 7 2 plus y - 5 2 equals 16 Enter your answer as an ordered pair?

I think this means (x+7)squared + (y-5)squared =4squared, which represents a circle centred at -7,+5


How do you solve x squared plus y squared equals 13?

The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.


What is the approximate area of a circle with a radius of 3 feet?

Area of a circle equals pi (~3.14) multiplied by the radius squared. So to find the area of that circle your equation is (3.14)(3)^2 which equals approximately 27.


What is the equation for a circle with its center at the origin and a tangent whose equation is y equals 7?

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Does the equation a squared plus b squared equals c squared classify as a quadratic equation?

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No. C = 2*pi*r is the equation representing the circumference of a circle. The area of a circle is equal to pi*(r^2).


Where is the center of the circle given by the equation x plus 5 times 2 plus y - 3 times 2 equals 25 in an ordered pair?

Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.


What is the relationship between the area of a circle and its radius squared?

The area of a circle is defined by the equation A = πr^2 where π = pi (3.14...) A = Area r^2 = radius squared So, the radius of a circle squared multiplied by pi equals the area.


What is the center of a circle for the equation 3x2 plus 3y2 - 30x plus 27 equals 0?

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What are the center and radius of the circle whose equation is 2x squared plus 2y squared -8x -12y -6 equals 0?

Divide all terms by 2 and complete the square for x and y:- So: (x-2)^2 + (y-3)^2 = 16 Therefore centre of circle is at (2, 3) and its radius is 4


What is the centre and radius of a circle when x squared plus y squared -4x -2y -4 equals 0?

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What is the center and the radius of the circle with this equation x2 plus y2 equals 121?

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Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 equals 25 Enter your answer as an ordered pair?

It's at the point ( -5, 3 ) The general formula of a circle is given by the equation: ( x - h )2 + ( y - k )2 = r2 Where the point ( h, k ) is the center of the circle, and r is the radius of the circle. In the equation ( x + 5 )2 + ( y - 3 )2 = 25 The first group of terms isn't subtracted. Rather than x + 5, this is actually x - -5. The center of the circle, then, is the point ( -5, 3 )


Is x squared plus 7x-30 equals 0 a linear equation?

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Where is the center of the circle given by the equation x plus 4 2 plus y - 3 2 equals 4?

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Where is the center of the circle given by the equation x plus 7 2 plus y - 5 2 equals 16?

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What is the center and area of the circle x2 plus 4x plus y2 -18y plus 59 equals 0?

Equation of circle: x^2 +4x +y^2 -18y +59 = 0 Completing the squares: (x +2)^2 +(y -9)^2 = 26 which is radius squared Center of circle: (-2, 9) Area of circle: pi times 26 = 81.681 square units to three decimal places


If the area of a circle is 25 square units what is the radius of the circle?

area equals pi r squared therefor r squared equals area over pi. Now find square root of r squared and you have "R" (radius) = 2.821