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From the information given the circle centre is (-4,3).

Since no sign is given with '4' , it is assumed it is positive.

The '= 4' is radius squared (Pythagoras).

So the whole equation becomes

(x --4)^2 + (y - 3)^2= 4 = 2^2 =>

( x + 4)^2 + ( y - 3)^2 = 2^2 (Note the Pythagorean equation).

Multiply out

x^2 + 8x + 16 + y^2 - 6y + 9 = 4

Collect terms

x^2 + y^2 + 8x - 6y + 21 = 0

The equation of the given circle.

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lenpollock

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1y ago
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12y ago

(-4,3)

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Q: Where is the center of the circle given by the equation x 4 squared y - 3 squared equals 4?
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