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What is Y equals 2xsquared-12x plus 6?
"y = 2x2 - 12x + 6" is a quadratic equation which describes a parabola whose vertex occurs at the point (3, -12) and which has a range of -12 → ∞. It intercepts the x-axis at the points (3 - √6, 0) and (3 + √6, 0).
Find the x-coordinate of the vertex of this parabola fx equals xsquared plus 6x-2?
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What is the length of the focal width x 2 equals 12y?
The given equation (x^2 = 12y) represents a parabola that opens upwards. The length of the focal width (the distance between the two points on the parabola where it intersects a line parallel to the directrix) is equal to (4p), where (p) is the distance from the vertex to the focus. For this parabola, (4p = 12), so the focal width is (12). Therefore, (12) is the length of the focal width.
The vertex of a parabola is (-2 -20) and its intercept is (0 -12).?
To find the equation of the parabola, we can use the vertex form, which is (y = a(x - h)^2 + k), where ((h, k)) is the vertex. Substituting the vertex ((-2, -20)), the equation becomes (y = a(x + 2)^2 - 20). Using the intercept ((0, -12)) to find (a), we substitute (x = 0) and (y = -12), resulting in (-12 = a(0 + 2)^2 - 20). Solving for (a) gives (a = 2), leading to the final equation (y = 2(x + 2)^2 - 20).
What is 12 plus 9 equals?
12 plus 9 equals 21.
What is Y equals 2xsquared-12x plus 6?
"y = 2x2 - 12x + 6" is a quadratic equation which describes a parabola whose vertex occurs at the point (3, -12) and which has a range of -12 → ∞. It intercepts the x-axis at the points (3 - √6, 0) and (3 + √6, 0).
Find the x-coordinate of the vertex of this parabola fx equals xsquared plus 6x-2?
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How do you find the vertex of the parabola 3x squared -x plus 4?
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Find equation what parabola its vertex is 0 0 and it passes through point 2 12 express the equation in standard form?
Y=3x^2 and this is in standard form. The vertex form of a prabola is y= a(x-h)2+k The vertex is at (0,0) so we have y=a(x)^2 it goes throug (2,12) so 12=a(2^2)=4a and a=3. Now the parabola is y=3x^2. Check this: It has vertex at (0,0) and the point (2,12) is on the parabola since 12=3x2^2
What is the length of the focal width x 2 equals 12y?
The given equation (x^2 = 12y) represents a parabola that opens upwards. The length of the focal width (the distance between the two points on the parabola where it intersects a line parallel to the directrix) is equal to (4p), where (p) is the distance from the vertex to the focus. For this parabola, (4p = 12), so the focal width is (12). Therefore, (12) is the length of the focal width.
What does 12 plus 12 plus 12 plus 12 plus 12 plus 12 equals?
it equals 72. just do 12 X 6
The vertex of a parabola is (-2 -20) and its intercept is (0 -12).?
To find the equation of the parabola, we can use the vertex form, which is (y = a(x - h)^2 + k), where ((h, k)) is the vertex. Substituting the vertex ((-2, -20)), the equation becomes (y = a(x + 2)^2 - 20). Using the intercept ((0, -12)) to find (a), we substitute (x = 0) and (y = -12), resulting in (-12 = a(0 + 2)^2 - 20). Solving for (a) gives (a = 2), leading to the final equation (y = 2(x + 2)^2 - 20).
What is 6 plus 12 plus 12 plus 16 plus 24 equals?
it equals 70
What is the x-coordinate of the of the vertex of y equals -3x2 plus 12x-5?
You can find the x-coordinate of it's vertex by taking it's derivative and solving for zero: y = -3x2 + 12x - 5 y' = -6x + 12 0 = -6x + 12 6x = 12 x = 2 Now that we have it's x coordinate, we can plug it back into the original equation to find it's y coordinate: y = -3x2 + 12x - 5 y = -3(2)2 + 12(2) + 5 y = -12 + 24 + 5 y = 17 So the vertex of the parabola y = -3x2 + 12x - 5 occurs at the point (2, 17).
What is 12 plus 9 equals?
12 plus 9 equals 21.
plus plus equals 24?
12+12
What is y equals 2xsquared-5x -12 in vertex form?
The curve turns at a minimum: (2.5, -12)
