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Q: Which equation is a line that is perpendicular to the line of 8x 1 algebra 2?
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The line given by the equation y equals -8x is perpendicular to what line?

It would be perpendicular to a line with the equation Y = 1/8 X.


What is the slope of a line perpendicular to the graph of y -8x 20?

Do you mean y = -8x+20 Then if so the perpendicular slope is positive 1/8.


What is the equation of a straight line that cuts through the middle of the points of -1 3 and -2 -5 at right angles on the Cartesian plane showing work?

The equation will be a perpendicular bisector equation of the given points:- Points: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular equation: y--1 = -1/8(x--3/2) => y = -1/8x-3/16-1 Therefore the perpendicular bisector equation is: y = -1/8x -19/16


What is the perpendicular bisector equation that meets the line segment of -1 3 and -2 -5?

Midpoint: (-3/2, -1) Gradient or slope: 8 Perpendicular slope: -1/8 Equation: y- -1 = -1/8(x- -3/2) y = -1/8x -3/16 -1 y = -1/8x -19/16 The perpendicular equation can be expressed in the form of: 2x+16y+19 = 0


What is 8x plus 5y100?

If you mean 8x+5y = 100 then it is a straight line equation


What is 11x plus 5 equals 8x plus 20 in algebra?

That's an equation where x = 5


How do you do (5x2 8x)-(3x2-x)?

In algebra and mathematics the simple above equation can be written and simplified as follows . (5x2 8x)-(3x2-x) = 10 + 8x -6 +x = 4 +7x.


What is the equation of the straight line that passes through (82) and (8 -3)?

Find an equati find an equation for the line perpendicular to the line 8x - 8 y equals negative 2 having the same Y intercept as -6x + 2 y equals negative 8


What is the perpendicular bisector equation of the line joined by the points of -1 3 and -2 -5?

Points: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular bisector equation: y--1 = -1/8(x--3/2) => y = -1/8x-19/16


What is the slope of a line that is perpendicular to the graph of 8x plus y equals 6?

+ 1/8


What is the perpendicular bisector equation of the line segment whose endpoints are at -1 3 and -2 -5?

Endpoints: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular bisector equation: y --1 = -1/8--3/2 => y = -1/8x -19/16


What is -8x 2y-48?

If you mean -8x = 2y-48 then it is a straight line equation which can be expressed as y = -4x+24