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Which is the smallest no when divided by 12 and 18 leaves the remainder 9?
Wiki User
∙ 12y ago
(1) x/12=a+9, where a is an integer
(2) x/18=b+9, where b is an integer
3x(1) + 2x(2) gives
3x/36 + 2x/36 = 5x/36 = 3a+27+2b+18 = 3a+2b+45
5x/36=3a+2b+45
x=36(3a+2b+45)/5
x=36(3a+2b)/5+9
as 36 is not divisible by 5 then 3a+2b should be divisible by 5
then the smallest solution is a=0 and b=0
and x=9
Wiki User
∙ 12y ago
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