(1) x/12=a+9, where a is an integer
(2) x/18=b+9, where b is an integer
3x(1) + 2x(2) gives
3x/36 + 2x/36 = 5x/36 = 3a+27+2b+18 = 3a+2b+45
5x/36=3a+2b+45
x=36(3a+2b+45)/5
x=36(3a+2b)/5+9
as 36 is not divisible by 5 then 3a+2b should be divisible by 5
then the smallest solution is a=0 and b=0
and x=9
Try 30
12*1 + 3 = 15 12*2 + 3 = 27 12*4 + 3 = 51 when 51 divided by 15 gives the remainder as 6.
The remainder of any division MUST be smaller than the divisor. So no number divided by 10 or 7 can leave a remainder of 12. So review your question and post it when it makes sense.
51.8333
To determine the smallest number that must be added to 5621 to make it divisible by 12, we first find the remainder of 5621 when divided by 12. Dividing 5621 by 12 gives a remainder of 5. Therefore, to make 5621 divisible by 12, we need to add (12 - 5 = 7). Thus, the smallest number to add is 7.
Try 30
12*1 + 3 = 15 12*2 + 3 = 27 12*4 + 3 = 51 when 51 divided by 15 gives the remainder as 6.
36 divided by 28 would be 1 remainder 8and44 divided by 32 would be 1 remainder 12
66 66/16 = 4 and a remainder of 2 66/18 = 3 and a remainder of 12
12 is the smallest whole number that gives a remainder of 4 when it is divided by 8.
26
12
The remainder of any division MUST be smaller than the divisor. So no number divided by 10 or 7 can leave a remainder of 12. So review your question and post it when it makes sense.
51.8333
6.6667
23.0833
6