x = 2 + 2i
x = 2 - 2i
where i is the imaginary square root of -1.
Y = X2 - 4X + 12 set to 0 X2 - 4X + 12 = 0 subtract 12 from each side X2 - 4X = - 12 now, take the linear term ( - 4 ), halve it, square it and add it to both sides X2 - 4X + 4 = - 12 + 4 factor the left side, gather terms on the right (X - 2)2 = - 8 add 8 to each side (X - 2)2 + 8 = 0 ------------------------ (2, 8) ------------the vertex of this function
x2 + 4x - 96 = (x - 8)(x + 12).
x2 + 4x - 32 = (x + 8)*(x - 4)
x2+4x-32 = (x-4)(x+8) when factored
4x+8
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)
x2 - 4x - 32 = (x - 8)(x + 4)
Y = X2 - 4X + 12 set to 0 X2 - 4X + 12 = 0 subtract 12 from each side X2 - 4X = - 12 now, take the linear term ( - 4 ), halve it, square it and add it to both sides X2 - 4X + 4 = - 12 + 4 factor the left side, gather terms on the right (X - 2)2 = - 8 add 8 to each side (X - 2)2 + 8 = 0 ------------------------ (2, 8) ------------the vertex of this function
x2 + 4x - 96 = (x - 8)(x + 12).
x2 + 4x - 32 = (x + 8)*(x - 4)
x2+4x-32 = (x-4)(x+8) when factored
4x+8
If that's +4x, the answer is (x - 4)(x + 8) If that's -4x, the answer is (x + 4)(x - 8)
4x2+4x-8 4(x2+x-2) and (4x+8)(x-1)
4x-3-8 = 8 4x = 8+8+3 4x = 19 x = 4 and 3/4
x2 + 4x = 1 x2 + 4x - 1 = 0 in the quadratic formula (b2+- Sqr(4ac))/2a, a = 1 b = 4 c = -1 so x = 8 +- i
4x-8-2 can be more easily written as 4x-10. The solution to this equation would be 5/2