x = 2 + 2i
x = 2 - 2i
where i is the imaginary square root of -1.
x2 + 4x - 96 = (x - 8)(x + 12).
x2 + 4x - 32 = (x + 8)*(x - 4)
x2+4x-32 = (x-4)(x+8) when factored
4x+8
If that's +4x, the answer is (x - 4)(x + 8) If that's -4x, the answer is (x + 4)(x - 8)
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)
x2 - 4x - 32 = (x - 8)(x + 4)
x2 + 4x - 96 = (x - 8)(x + 12).
x2 + 4x - 32 = (x + 8)*(x - 4)
x2+4x-32 = (x-4)(x+8) when factored
4x+8
If that's +4x, the answer is (x - 4)(x + 8) If that's -4x, the answer is (x + 4)(x - 8)
4x2+4x-8 4(x2+x-2) and (4x+8)(x-1)
x2 + 4x = 1 x2 + 4x - 1 = 0 in the quadratic formula (b2+- Sqr(4ac))/2a, a = 1 b = 4 c = -1 so x = 8 +- i
4x-3-8 = 8 4x = 8+8+3 4x = 19 x = 4 and 3/4
4x-8-2 can be more easily written as 4x-10. The solution to this equation would be 5/2
That depends on what you're doing to the 8. It's either 4(x2 + 2) or 4(x2 - 2)