Q: Which is the solution set for x2 - 4x 8?

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x2 + 4x - 96 = (x - 8)(x + 12).

x2 + 4x - 32 = (x + 8)*(x - 4)

x2+4x-32 = (x-4)(x+8) when factored

4x+8

If that's +4x, the answer is (x - 4)(x + 8) If that's -4x, the answer is (x + 4)(x - 8)

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x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)

x2 - 4x - 32 = (x - 8)(x + 4)

x2 + 4x - 96 = (x - 8)(x + 12).

x2 + 4x - 32 = (x + 8)*(x - 4)

x2+4x-32 = (x-4)(x+8) when factored

4x+8

If that's +4x, the answer is (x - 4)(x + 8) If that's -4x, the answer is (x + 4)(x - 8)

4x2+4x-8 4(x2+x-2) and (4x+8)(x-1)

x2 + 4x = 1 x2 + 4x - 1 = 0 in the quadratic formula (b2+- Sqr(4ac))/2a, a = 1 b = 4 c = -1 so x = 8 +- i

4x-3-8 = 8 4x = 8+8+3 4x = 19 x = 4 and 3/4

If: y = x2-4x+8 and y = 8x-x2-14 Then: x2-4x+8 = 8x-x2-14 So: 2x2-12x+22 = 0 Discriminant: 122-(4*2*22) = -32 Because the discriminant is less than 0 there is no actual contact between the given parabolas

That depends on what you're doing to the 8. It's either 4(x2 + 2) or 4(x2 - 2)