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X-y equals 1 and 8x plus 3y equals 4 solve for y and explain?
Plaigerizemeplease
x = y + 1 so 8 (y + 1) + 3y = 4, ie 8y + 8 + 3y = 4 ie 11y = -4 so y = -4/11 and x = 7/11
Check: 56/11 - 12/11 = 44/11 = 4 QED
Another explanation:
This is a simultaneous equation and can be solved using the elimination method in the form of:
8x+3y = 4
3(x-y = 1)
Multiply all terms in the bottom equation by 3:
8x+3y = 4
3x-3y = 3
Add both equations together in order to eliminate y:
11x = 7
Divide both sides by 11 to find the value of x:
x = 7/11
Substitute the value of x into the original equations to find the value of y:
Therefore: x = 7/11 and y = -4/11
Proof: If x-y = 1 then 7/11 - - 4/11 = 1 (remember that in maths a - - equals +)
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∙ 14y ago
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