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What is the solution of this quadratic equation x2 plus 3x-10 equals 0?
x2 + 3x - 10 = (x + 5)(x - 2) ⇒ x = -5 or 2
X2 plus 3x plus 7 equals 5?
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
If 3x-1 equals 11 what is the value of x2 plus 2?
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
-x2 plus 3x equals -4?
-2x + 3x = -4 By combining like terms we get: x = -4.
X2 plus 3x-7 equals 5x plus 8?
x2 + 3x - 7 = 5x + 8; thus, x2 + 3x - 7 - 5x - 8 = x2 - 2x - 15 = (x - 5)(x + 3) = 0. Therefore the solution is x = 5 or -3.
What is the solution of this quadratic equation x2 plus 3x-10 equals 0?
x2 + 3x - 10 = (x + 5)(x - 2) ⇒ x = -5 or 2
How do you solve x2 plus 3x plus 3 0?
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
What are the solutions for x2 plus 3x-10 equals 0?
x = -5 x = 2
X2 plus 3x plus 7 equals 5?
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
What is the answer for 3x equals x2 plus 2?
x = 2
X2 - 3x - 10 equals?
If you factor x2 - 3x - 10, you'll get (x-5) (x+2). If your equation is x2 - 3x -10 = 0, then x = 5, and x = -2.
Can you put the equation x2 - 5 -4x2 plus 3x equals 0 in the form ax2 plus bx plus c equals 0?
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
How do you find the descending order of x2 plus 3x-10?
x2+3x-10 = (x+5)(x-2) when factored
If 3x-1 equals 11 what is the value of x2 plus 2?
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
-x2 plus 3x equals -4?
-2x + 3x = -4 By combining like terms we get: x = -4.
X2 plus 3x-7 equals 5x plus 8?
x2 + 3x - 7 = 5x + 8; thus, x2 + 3x - 7 - 5x - 8 = x2 - 2x - 15 = (x - 5)(x + 3) = 0. Therefore the solution is x = 5 or -3.
Find the value of x. X2 plus 1 equals 3x plus 11?
x=-11
