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x4+ 3x3 - x2 - 9x - 6 = 0 (rewrite the equation, let -9x = -3x - 6x)
x4+ 3x3 - x2 - 3x - 6x - 6 = 0 (group terms)
(x4 - x2) + (3x3 - 3x) - (6x + 6) = 0
x(x2 - 1) + 3x(x2 - 1) - 6(x + 1) = 0 (use the difference of the squares, a2 - b2 = (a - b)(a + b))
x(x - 1)(x + 1) + 3x(x - 1)(x + 1) - 6(x + 1) = 0 (the common factor is x + 1)
(x + 1)[x(x - 1) + 3x(x - 1) - 6] = 0
(x + 1)(x2 - x + 3x2 - 3x - 6) = 0 (work with like terms)
(x + 1)(4x2 - 4x - 6) = 0 (factor out 2)
2(x + 1)(2x2 - 2x - 3) = 0
x + 1 = 0 or 2x2 - 2x - 3 = 0
x = -1 or
x = [-2 +/- square root of ((-2)2 - 4(2)(-3))]/2(2)
x = [-2 +/- square root of (4 + 24)]/4
x = -1/2 +/- (square root of 28)/4
x = -1/2 +/- 1/2(square root of 7)
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What answer is equal to the sum in the expression below (3x3 plus 4x2 - 2x plus 1) plus (x4 - x3 plus 5x2 plus 2x plus 3)?
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
What is x when X4 plus 3x3 - x2 - 9x - 6 equals 0?
x4 + 3x3 - x2 - 9x - 6 = 0 x4 + x3 + 2x3 + 2x2 - 3x2 - 3x - 6x - 6 = 0 x3(x + 1) + 2x2(x + 1) - 3x(x + 1) - 6(x + 1) = 0 (x + 1)(x3 + 2x2 - 3x - 6) = 0 (x + 1)[x2(x + 2) - 3(x + 2)] = 0 (x + 1)(x + 2)(x2 - 3) = 0 So x + 1 = 0 so that x = -1 or x + 2 = 0 so that x = -2 or x2 - 3 = 0 so that x = +/- sqrt(3)
X4-2x3 plus 2x2 plus x plus 4 divided by x2 plus x plus 1 solutions?
(x4 - 2x3 + 2x2 + x + 4) / (x2 + x + 1)You can work this out using long division:x2 - 3x + 4___________________________x2 + x + 1 ) x4 - 2x3 + 2x2 + x + 4x4 + x3 + x2-3x3 + x2 + x-3x3 - 3x2 - 3x4x2 + 4x + 44x2 + 4x + 40R∴ x4 - 2x3 + 2x2 + x + 4 = (x2 + x + 1)(x2 - 3x + 4)
What is the derivative of x to the fourth power -3x cubed plus 5x2 divided by x squared?
If you mean: f(x) = x4 - 3x3 + 5x2 / x2 then: f(x) = x4 - 3x3 + 5 ∴ f'(x) = 4x3 - 9x2 If you mean: f(x) = (x4 - 3x3 + 5x2) / x2 then: f(x) = x2 - 3x + 5 ∴ f'(x) = 2x - 3
1 plus x plus x2 plus x3 plus x4 plus plus x24 equals 49x25?
No.
What answer is equal to the sum in the expression below (3x3 plus 4x2 - 2x plus 1) plus (x4 - x3 plus 5x2 plus 2x plus 3)?
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
What is x when X4 plus 3x3 - x2 - 9x - 6 equals 0?
x4 + 3x3 - x2 - 9x - 6 = 0 x4 + x3 + 2x3 + 2x2 - 3x2 - 3x - 6x - 6 = 0 x3(x + 1) + 2x2(x + 1) - 3x(x + 1) - 6(x + 1) = 0 (x + 1)(x3 + 2x2 - 3x - 6) = 0 (x + 1)[x2(x + 2) - 3(x + 2)] = 0 (x + 1)(x + 2)(x2 - 3) = 0 So x + 1 = 0 so that x = -1 or x + 2 = 0 so that x = -2 or x2 - 3 = 0 so that x = +/- sqrt(3)
X4-2x3 plus 2x2 plus x plus 4 divided by x2 plus x plus 1 solutions?
(x4 - 2x3 + 2x2 + x + 4) / (x2 + x + 1)You can work this out using long division:x2 - 3x + 4___________________________x2 + x + 1 ) x4 - 2x3 + 2x2 + x + 4x4 + x3 + x2-3x3 + x2 + x-3x3 - 3x2 - 3x4x2 + 4x + 44x2 + 4x + 40R∴ x4 - 2x3 + 2x2 + x + 4 = (x2 + x + 1)(x2 - 3x + 4)
What is the derivative of x to the fourth power -3x cubed plus 5x2 divided by x squared?
If you mean: f(x) = x4 - 3x3 + 5x2 / x2 then: f(x) = x4 - 3x3 + 5 ∴ f'(x) = 4x3 - 9x2 If you mean: f(x) = (x4 - 3x3 + 5x2) / x2 then: f(x) = x2 - 3x + 5 ∴ f'(x) = 2x - 3
X4 equals 2x3 plus 1?
Not necessarily.
How many corfficients does -3x3 plus x2 plus 17 plus 6x4 have?
- 3X3 + X2 + 17 + 6X4Three. I will put the coefficients in parentheses.(- 3 )X3 + (1)X2 + 17 + (6)X4=========================( remember, 1 is always an implied coefficient )
1 plus x plus x2 plus x3 plus x4 plus plus x24 equals 49x25?
No.
Factor x to the fourth power plus 2x to the third power minus 9x to the second power plus 18x?
x4 + 2x3 - 9x2 + 18x = x(x3 + 2x2 - 9x + 18) which I do not think can be factorised further.
X4 plus 3x3-10x2 equals 0?
Given: x4 + 3x3 - 10x2 = 0 You can start by dividing both sides of the equation by x2: x2 + 3x - 10 = 0 Then factor out the left side of the equation into simpler terms: (x + 5)(x - 2) = 0 For the result to be 0, either of the terms in brackets on the left must equal 0, so that means there are two answers: x = -5, x = 2
X4 plus x2 equals 1?
4X + 2x = 1. Where x = 0.166666666666666666666666666666666666666 recurring.
What is 7 x4 equals?
28 is.
What is x4 plus x4?
One of anything plus another one of them is always two of the same thing.
