Eqn 1: x - 2y = 3
Eqn 2: 5x + 3y = 2
5 times Eqn 1: 5x - 10y = 15
Eqn 2 - 5*Eqn 1: 0x + 13y = -13 so that 13y = -13 or y = -1
Substitute in Eqn 1: x + 2*1 = 3
x + 2 = 3
x = 1
Solution: x = 1, y = -1
9y-3y=6y; 6y+2y=8y; so your answer is 8y
4n + 3y
y = -1
are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}
(-1, 0)
3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8
5y-2y= 3y+2 5y-2y-3y= 2 0y= 2
2y + 3 = 3y + 9 2y - 3y = 9 - 3 or -y = 6 so y = -6
6y
9y-3y=6y; 6y+2y=8y; so your answer is 8y
If 3y = 12, 2y = 8
The lines are perpendicular, and intersect at the point (1.35, 3.55) .
4n + 3y
y = -1
are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}
3y + 2y + 4 + 1 = 805y + 5 = 805y = 75y = 15
(-1, 0)