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22 is the answer
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Which 2 numbers you multiply and you get 24 and when you subtract them you get 11?
So if the two numbers are x and y: x*y = 24, and y - x = 11. So y = x + 11, and then x*(x+11) = 24 : x2 + 11*x - 24 = 0. So x = (-11+SQRT(217))/2 or (-11-SQRT(217))/2, which is 1.865459931 or -12.865459931. Substituting into one of the equations above: {x = 1.865459931 and y = 12.865459931} or {x = -12.865459931 and y = -1.865459931}
Which two numbers add up to 10 muliply to -11?
-1
5x-3y equals 11 if x is 0 what is y?
so -3y = 11 ie y = -11/3 or -3 and 2/3
What two numbers when added together equals -11 when multiplied equals -8160?
Let the two numbers be x & y. Two Equations: x + y = -11 And x*y = -8160.rearrange first eq: [y = -11 -x] and substitute into second eq: (-11 - x)*x = -8160-x^2 - 11*x = -8160 --> x^2 + 11*x - 8160 = 0. This is a quadratic. Solve for x = -96 and 85. Either of these two numbers substituted into the first equation will produce the other number for y, so the 2 numbers are -96 and 85.
The sum of two numbers is 16 and the sum of their squares is 146 find the two numbers?
x+y=16; y=16-xx^2 + y^2=146; y=±√(146-x^2) So, 16-x=±√(146-x^2)(16-x)^2=146-x^2256-32x+x^2=146-x^22x^2-32x+110=0x^2-16x+55=0Quadratic formula:x=[16±√(256-220)]/2x=(16±6)/2x=8±3x=11 or x=5. Plug these values back into the original equations, and you will see that y also equals 11 or 5. So, the two pairs of numbers that satisfy the original equations are: x=11, y=5; and x=5, y=11
What is y equals x plus 2 y equals 2-x?
y = x + 2 y = 2 - x so x + 2 = 2 - x Combining like terms: 2x = 0 so that x = 0 and then, from the first equation, y = 2
Y - 11 equals 14 x - 2?
(2, 11)
Find two numbers whose sum is 48 and whose difference is 26?
Two ways to do this: x + y = 48 y = 48-x x - y = 26 x - 48 + x = 26 2x = 74 x = 37 y = 48-37 = 11 so 37 and 11 Other method x + y=48 x - y=26 Subtract line 1 from line 2 2y = 22 y = 11 then solve for x x +11=48 x = 37 again you get 37 and 11
Two integers have a difference of -11 and a sum of -3 What are the integers?
Two integers (X & Y). X+Y=-3, X-Y=-11. x=-11+y --> (x)+y=-3 --> (-11+y)+y=-3 --> y=4 x=-11+4=-7 Hope that helps! Two integers (X & Y). X+Y=-3, X-Y=-11. x=-11+y --> (x)+y=-3 --> (-11+y)+y=-3 --> y=4 x=-11+4=-7 Hope that helps!
What is the GCF of 110 and 11?
GCF of x and y is y if x is divisible by y. Here 110 is divisible by 11, so GCF(110,11) = 11.
What are the points of intersection between the line 3x -y equals 5 and the curve 2x squared plus y squared equals 129?
If: 3x-y = 5 then y^2 = (3x_5)^2 => 9x^2 -30x+25 If: 2x^2 + y^2 = 129 then y^2 = 129-2x^2 So: 9x^2 -30x+25 = 129-2x^2 Transposing terms: 11x^2 -30x -104 = 0 Factorizing the above: (11x-52)(x+2) = 0 meaning x = 52/11 or x = -2 By substituting x into the original equation intersections are at: (52/11, 101/11) and (-2, -11)
What are the solutions to x square -xy -y square equals -11 and 2x plus y equals 1 showing work?
If: 2x+y = 1 then y = 1-2x If: x^2 -xy -y^2 = -11 then x^2 -x(1-2x) -(1-2x)^2 -11 = 0 Multiplying out the brackets: x^2 -x+2x^2 -1+4x -4x^2+11 = 0 Collecting like terms: -x^2+3x+10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: when x = 5 then y = -9 and when x = -2 then y = 5
