Find two numbers whose sum is 48 and whose difference is 26?

Answer 1

Two ways to do this:

x + y = 48

y = 48-x

x - y = 26

x - 48 + x = 26

2x = 74

x = 37

y = 48-37 = 11

so 37 and 11

Other method

x + y=48

x - y=26

Subtract line 1 from line 2

2y = 22

y = 11

then solve for x

x +11=48

x = 37

again you get 37 and 11