0
That means y = a*x^3 + b*x^2 + c*x + d, which represents a curve in the xy graph. a, b, and c are called coefficients. a is the coefficient for the cubic term (x^3). b is for the square term (x^2). c the linear coefficient. d is the constant.
If a, b, c, and d are assigned values. For example, a = 1; b =0; c = -1; and d = 4. Then the equation becomes y = x^3 - x + 4. We can substitute real values for x to obtain a corresponding value for each y. For example:
x y
0 4
1 4
2 10
and so on. We can then plot a curve on the graph paper.
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What is the equation for a cubic graph with points (42)?
y= ax^3+bx^2+cx-42, assuming the point was (0, 42)
If x is between a and c how are ax and ac related?
If a,b, and c are positive a < x < b means ax < cx If a,b , and c are negative a < x < b means ax > cx
What is bx plus 2b plus cx plus 2c?
factor b(x+2) + c(x+2) (b+c)(x+2) need more info for futher analysis.
How do you add multidigit numbers in 8086?
print macro msg lea dx,msg movah,09h int 21h endm read macro n,j1,j2 mov cx,0ah j1:mov ah,01h int 21h cmpal,0dh je j2 sub al,30h mov bl,al mov ax,n mul cx xor bh,bhadd ax,bx mov n,axjmp j1 j2 :nop endm .model small .stack 100h .data msg1 db 10,13,'Enter the 1st number: $' msg2 db 10,13,'Enter the 2nd number: $' msg3 db 10,13,'The Sum= $' num1 dw 0 num2 dw 0 .code main proc mov ax,@data movds,ax print msg1 ;reading 1st multidigit number read num1,jump1,jump2 print msg2 ;reading 2nd multidigit number read num2,jump3,jump4 ;finding sum mov ax,num1 add ax,num2 ;printing number mov bx,000ah xorcx,cx ;push into stack p1:xordx,dx div bx pushdx inc cx cmp ax,0000h jne p1 print msg3 ;pop from stack display:popdx add dl,30h movah,02h int 21h loop display movah,4ch int 21h main endp end
Solve x equals cx equals AA plus 1?
x = cx = aa+1 If x = cx, then c = 1 aa = a2 if a2 + 1 = x, then a2 = x-1 short of parametrization, this is the answer for this equation, but if you doing advanced maths, then let x= t (teR) a2 = -1 +t (teR)
What is x as the subject what equation ax plus b equals cx plus d?
x = (d-a)/(a-c)
Program to find GCF and LCM of 2 numbers in 8086?
This is my program, and it works with all no.s except multiples of 2. org 100h MOV CX,0000H MOV DS,CX MOV SS,CX MOV SI,5000H MOV DI,5002H MOV [ DS:SI ],10H MOV [ DS:DI ],20H MOV SP,600FH MOV BX,[ DS:SI ] CMP BX,[ DS:DI ] JZ E1 JC SMALL THIK: MOV BX,0001H OK: MOV AX,[ DS:SI ] MOV DX,0000H DIV BX CMP DX,0000H JZ L1 L2: INC BX CMP [ DS:DI ],BX JC HCF JMP OK SMALL: MOV AX,[ DS:DI ] MOV [ DS:DI ],BX MOV [ DS:SI ],AX JMP THIK L1: MOV AX,[ DS:DI ] DIV BX CMP DX,0000H JNZ L2 PUSH BX INC CX JMP L2 HCF: MOV AX,0001H AGAIN: POP BX MUL BX DEC CX JNZ AGAIN LCM: MOV BX,AX MOV AX,[ DS:SI ] MUL [ DS:DI ] DIV BX E1 : INC DI INC DI MOV [ DS:DI ],AX ret
Compute the factorial of n using 8086 microprocessors?
code segment assume cs:code,ds:code mov bx,1200h mov cx,[bx] mov ax,01h l1:mul cx dec cl jnz l1 mov[bx+2],ax mov ah,4ch int 21h code ends end
What are different types of registers in a basic computer?
computer has different registers each of which has different functions. ax - accumulator register bx - base register cx - counter register computer has different registers each of which has different functions. ax - accumulator register bx - base register cx - counter register
If ax equals b minus cx then x equals?
x = b/(a + c)
Write an assembly language program for arranging nos in the ascending order?
title ascending order using bubble sort .model small .stack 64 .data a db 34h,78h,56h,47h si_ze dw $-a ;si_ze=no of elements .code bubsort: mov ax,@data mov ds,ax mov bx,si_ze dec bx ;bx=no of passes needed to complete sorting(n-1) outlup: mov cx,bx ;cx=no of comparisions to be performed in a pass mov si,0 inlup: mov al,a[si] inc si cmp al,a[si] jb go_on xchg al,a[si] mov a[si-1],al go_on: loop inlup ;dec cx,until cx=0 dec bx jnz outlup int 3 ;breakpoint interrupt align 16 end bubsort
What is the equation for a cubic graph with points (42)?
y= ax^3+bx^2+cx-42, assuming the point was (0, 42)
Suppose AX and BX contains signed numbers write some code to put the bigger one in CX and if they are equal add them in AX?
Da program pa yakho obo olambawa
What is the scale of c double sharp major?
The Cx Major scale will have 14 sharps (all 7 double-sharps), and the scale goes like this: Cx, Dx, Ex (same as F♯), Fx, Gx, Ax, Bx (same as C♯), Cx.
What is the size of flag register?
All of the 8086/8088 registers, AX, BX, CX, DX, SP, BP, SI, DI, CS, DS, SS, ES, IP, and FLAGS, are 16 bit registers. The AX, BX, CX, and DX registers may also be viewed as 8 eight bit registers AH/AL, BH/BL, CH/CL, and DH/DL.
What is the 8086 program to find the sum of n numbers?
8096
Implement an assembly code that counts the number of vowels in a given string?
.MODEL SMALL .STACK 100H .DATA PROMPT_1 DB 'Enter a string : $' PROMPT_2 DB 0DH,0AH,'No. of Vowels = $' PROMPT_3 DB 0DH,0AH,'No. of Consonants = $' STRING DB 50 DUP (?) C_VOWELS DB 'AEIOU' S_VOWELS DB 'aeiou' C_CONSONANTS DB 'BCDFGHJKLMNPQRSTVWXYZ' S_CONSONANTS DB 'bcdfghjklmnpqrstvwxyz' .CODE MAIN PROC MOV AX, @DATA ; initialize DS and ES MOV DS, AX MOV ES, AX LEA DX, PROMPT_1 ; load and display the string PROMPT_1 MOV AH, 9 INT 21H LEA DI, STRING ; set DI=offset address of variable STRING CALL READ_STR ; call the procedure READ_STR XOR DX, DX ; clear DX LEA SI, STRING ; set SI=offset address of variable STRING OR BX, BX ; check BX for 0 JE @EXIT ; jump to label @EXIT if BX=0 @COUNT: ; jump label LODSB ; set AL=DS:SI LEA DI, C_VOWELS ; set DI=offset address of variable C_VOWELS MOV CX, 5 ; set CX=5 REPNE SCASB ; check AL is capital vowel or not JE @INCREMENT_VOWELS ; jump to label @INCREMENT_VOWELS if AL is ; capital vowel LEA DI, S_VOWELS ; set DI=offset address of variable S_VOWELS MOV CX, 5 ; set CX=5 REPNE SCASB ; check AL is small vowel or not JE @INCREMENT_VOWELS ; jump to label @INCREMENT_VOWELS if AL is ; small vowel LEA DI, C_CONSONANTS ; set DI=offset address of variable ; C_CONSONANTS MOV CX, 21 ; set CX=21 REPNE SCASB ; check AL is capital consonant or not JE @INCREMENT_CONSONANTS ; jump to label @INCREMENT_CONSONANTS if AL ; is capital consonant LEA DI, S_CONSONANTS ; set DI=offset address of variable ; S_CONSONANTS MOV CX, 21 ; set CX=21 REPNE SCASB ; check AL is small consonant or not JE @INCREMENT_CONSONANTS ; jump to label @INCREMENT_CONSONANTS if AL ; is small consonants JMP @NEXT ; otherwise, jump to label @NEXT @INCREMENT_VOWELS: ; jump label INC DL ; increment DL JMP @NEXT ; jump to label @NEXT @INCREMENT_CONSONANTS: ; jump label INC DH ; increment DH @NEXT: ; jump label DEC BX ; decrement BX JNE @COUNT ; jump to label @COUNT while BX!=0 @EXIT: ; jump label MOV CX, DX ; set CX=DX LEA DX, PROMPT_2 ; load and display the string PROMPT_2 MOV AH, 9 INT 21H XOR AX, AX ; clear AX MOV AL, CL ; set AL=CL CALL OUTDEC ; call the procedure OUTDEC LEA DX, PROMPT_3 ; load and display the string PROMPT_3 MOV AH, 9 INT 21H XOR AX, AX ; clear AX MOV AL, CH ; set AL=CH CALL OUTDEC ; call the procedure OUTDEC MOV AH, 4CH ; return control to DOS INT 21H MAIN ENDP READ_STR PROC ; this procedure will read a string from user and store it ; input : DI=offset address of the string variabel ; output : BX=number of characters read ; : DI=offset address of the string variabel PUSH AX ; push AX onto the STACK PUSH DI ; push DI onto the STACK CLD ; clear direction flag XOR BX, BX ; clear BX @INPUT_LOOP: ; loop label MOV AH, 1 ; set input function INT 21H ; read a character CMP AL, 0DH ; compare AL with CR JE @END_INPUT ; jump to label @END_INPUT if AL=CR CMP AL, 08H ; compare AL with 08H JNE @NOT_BACKSPACE ; jump to label @NOT_BACKSPACE if AL!=08H CMP BX, 0 ; compare BX with 0 JE @INPUT_ERROR ; jump to label @INPUT_ERROR if BX=0 MOV AH, 2 ; set output function MOV DL, 20H ; set DL=20H INT 21H ; print a character MOV DL, 08H ; set DL=08H INT 21H ; print a character DEC BX ; set BX=BX-1 DEC DI ; set DI=DI-1 JMP @INPUT_LOOP ; jump to label @INPUT_LOOP @INPUT_ERROR: ; jump label MOV AH, 2 ; set output function MOV DL, 07H ; set DL=07H INT 21H ; print a character MOV DL, 20H ; set DL=20H INT 21H ; print a character JMP @INPUT_LOOP ; jump to label @INPUT_LOOP @NOT_BACKSPACE: ; jump label STOSB ; set ES:[DI]=AL INC BX ; set BX=BX+1 JMP @INPUT_LOOP ; jump to label @INPUT_LOOP @END_INPUT: ; jump label POP DI ; pop a value from STACK into DI POP AX ; pop a value from STACK into AX RET READ_STR ENDP OUTDEC PROC ; this procedure will display a decimal number ; input : AX ; output : none PUSH BX ; push BX onto the STACK PUSH CX ; push CX onto the STACK PUSH DX ; push DX onto the STACK CMP AX, 0 ; compare AX with 0 JGE @START ; jump to label @START if AX>=0 PUSH AX ; push AX onto the STACK MOV AH, 2 ; set output function MOV DL, "-" ; set DL='-' INT 21H ; print the character POP AX ; pop a value from STACK into AX NEG AX ; take 2's complement of AX @START: ; jump label XOR CX, CX ; clear CX MOV BX, 10 ; set BX=10 @OUTPUT: ; loop label XOR DX, DX ; clear DX DIV BX ; divide AX by BX PUSH DX ; push DX onto the STACK INC CX ; increment CX OR AX, AX ; take OR of Ax with AX JNE @OUTPUT ; jump to label @OUTPUT if ZF=0 MOV AH, 2 ; set output function @DISPLAY: ; loop label POP DX ; pop a value from STACK to DX OR DL, 30H ; convert decimal to ascii code INT 21H ; print a character LOOP @DISPLAY ; jump to label @DISPLAY if CX!=0 POP DX ; pop a value from STACK into DX POP CX ; pop a value from STACK into CX POP BX ; pop a value from STACK into BX RET ; return control to the calling procedure OUTDEC ENDP END MAIN
