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Y equals x3 plus 4x - 3.6?
IMPOSSIBLE
What is the y intercept of 4x plus -3y equals -36?
I assume you mean. 4X - 3Y = -36 subtract 4X from each side -3Y = -4X -36 divide both sides by -3 Y = 4/3X + 12 12 is Y intercept
What is the ordered pair of 4x-4y12 and -7x 4y-36?
If you mean: 4x -4y = 12 and -7x +4y = -36 then x = 8 and y = 5
How do you show 4x equals y?
4x = y : or it can be written in the reverse order, y = 4x.
What is the answer to x4 plus x3 minus 14x2 plus 4x plus 6 divided by x minus 3?
The answer to x4+x3-14x2+4x+6 divided by x-3 is x3+4x2-2x-2
Y equals x3 plus 4x - 3.6?
IMPOSSIBLE
(4x-y) plus (-10 plus y) if x3 and y4?
If x = 3 and y = 4 then the answer is 2
What is the answer to this y 4x 9?
36
What is the y intercept of 4x plus -3y equals -36?
I assume you mean. 4X - 3Y = -36 subtract 4X from each side -3Y = -4X -36 divide both sides by -3 Y = 4/3X + 12 12 is Y intercept
What I helps you find the area under the curve y x3 4x-3.6?
Integration.
What I helps you to find the area under the curve y x3 4x - 3.6?
"integration"
What is 4x 9 equals y?
36
Four times a number added to another number is 36. Three Times the first number minus the other number is 20. Find the numbers.?
4x+y=36------y=36-4x 3x-y=20 3x-36+4x=20 7x=56 x=8 y=4
What is the ordered pair of 4x-4y12 and -7x 4y-36?
If you mean: 4x -4y = 12 and -7x +4y = -36 then x = 8 and y = 5
What are the x- and y-intercepts of the graph of 4x 3y equals 36?
I'll assume you mean the graph of 4x plus 3y = 36, since [4x*3y = 36] does not intersect either axis.If you only need to find the intercepts, and nothing else about the equation, then:the line intersects the x-axis when [y=0], so plug y=0 and solve for x:4*x + 3*0 = 36 --> 4*x = 36 --> x = 9, so it intercepts the x-axis at (9,0)for y-intercept, plug [x=0]: 4*0 + 3*y = 36 --> 3*y = 36 --> y = 12: at point (0,12)
What is the factor of x3 plus x2 plus 4x plus 4?
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
What I helps you to find the area under the curve y x3 4x-3.6?
if this is for www.mymaths.co.uk, integration is all you need. best regards, lokilotus
