The probability that each roll will be a 1, is 1/6 (a sixth) because there is one outcome of interest (getting a 1) and 6 possible outcomes (6 numbers on the die).
Probability rules mean that if you want the probability of getting outcome A and getting outcome B then the total probability is P(A) x P(B) where P(A) means the probability of getting outcome A).
In short if you want P(A and B) then this is P(A) x P(B)
Applied to this example if you want the probability of getting a 1 on each throw of the die (i.e. on all 3 throws) then the probability is given by:
P(1 on all three rolls) = P(1 on first roll) x P(1 on second role) x P(1 on third role)
P(1 on all three rolls) = 1/6 x 1/6 x 1/6
P(1 on all three rolls) = 1 / 216
It depends on what size die you use, what its labels are and how many rolls you make. For example using a standard six-sided die and one roll, the probability of no sixes is 5/6 or ~0.83; the probability of no sixes with 25 rolls is less than 0.01 or 1%. If you used a standard d3 (three-sided die) then the probability will always be 1 or 100%, since rolling a six is impossible; but if every side has '6' on it the probability is 0, since every roll must be a 6.
With a fair die, it is 1/216 in three rolls, but the probability increases to 1 (a certainty) as the number of rolls is increased.
assuming a single six sided die the probability of rolling a three is 1/6
1/6
It is approx 0.1974
3/18 I think
Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.
The probability of 3 specific dice rolls is the probability that each one will happen multiplied together. For instance, the probability of rolling 2 then 6 then 4 is the probability of all of these multiplied together: The probability of rolling 2 is 1/6. The probability of rolling 6 is 1/6. The probability of rolling 4 is 1/6. Multiply these together and we get the total probability as 1/216
Three times.
Assume the die is fair. What are the numbers on the four sides? How many times are you allowed to roll it? If the four numbers are 1,2,3 and 4 and you want the first three rolls to be 1,3,2 in that order, the probability is 1/4*1/4*1/4 = 1/64.
Probability = (1/6)3 = 1/216 =0.00463
It is 1/6.