It is approx 0.1974
It is 0.0227
evens says 4 * 6 = 24 rolls required for 4 shows so 4 shows in 16 = 16 : 24 = 5 to 8 against
2/12
No. p-values are probabilities but they are not the only ones.
It is 0.45
It is 0.0227
If you roll the die often enough, the probability of getting a 2 ones in a row is 1. In only 2 rolls, the answer is (1/6)*(1/6) = 1/36
evens says 4 * 6 = 24 rolls required for 4 shows so 4 shows in 16 = 16 : 24 = 5 to 8 against
The probability of of rolling three ones on three dice is (1 in 6)3, or 1 in 216, or about 0.004630.
The following is the probability of obtaining 4 ones IN THE FIRST FOUR rolls of a fair die. Pr(4 1's) = Pr(1)*Pr(1)*Pr(1)*Pr(1) since the events are independent. Pr(4 1's) = Pr(1)4 = (1/6)4 = 1/1296 = 0.000772
(1/6)^3 since each event is independent and each has a probability of 1/6.
When a die is rolled once, the probability of 1 showing up is 1/6 . When a die is rolled 14 times, the probability of 1 showing up 6 times is a binomial probability. Let x = number of times 1 shows up P(x=6) = 14C6 (1/6)^6 (5/6)^(14-6) = 14C6 (1/6)^6 (5/6)^8 = 0.014982
Probability = (1/6)3 = 1/216 =0.00463
There is a 6.667% chance (one in 15) of that happening. Math: p = (3/10)*(2/9) = .06667
1/6+1/6+1/6-1/6 =.333
The probability of rolling 3 ones with 4 dice is:4C3 (1/6)3 (5/6) = 0.015432098... ≈ 1.54%
If the number cubes are standard dice cubes, the odds of rolling 3 ones is 1 in 216.