If f(x)=x2+10, then f(x+h)=?f(x+h)=(x+h)2+10 (since f(x)=x2+10, substitute the x in x2 to (x+h)2)=(x+h)(x+h)+10 (then multiply (x+h) by (x+h) by doing the FOIL method)=x2+xh+xh+h2+10 (First: x*x, Outside: x*h, Inside: h*x, Last: h*h)=x2+2xh+h2+10 (combine like terms (xh+xh=2xh))So if f(x)=x2+10, then f(x+h)=x2+2xh+h2+10
2 hemispheres in a sphere.
A = h/2*(a + b) So 2A/h = a + b and therefore, a = 2A/h - b
76-2*6=444
The equation for the area of a triangle goes as followed: A = [(b)(h)]/2 A = Area b = base h = height Your known values are A = 30 h = 10 Unknown values b = ? Simply plug in your known values to find your unknown value: 30 = [(b)(10)]/2 (30)(2) = (b)(10) 60 = (b)(10) (60)/(10) = b b = 6
If f(x)=x2+10, then f(x+h)=?f(x+h)=(x+h)2+10 (since f(x)=x2+10, substitute the x in x2 to (x+h)2)=(x+h)(x+h)+10 (then multiply (x+h) by (x+h) by doing the FOIL method)=x2+xh+xh+h2+10 (First: x*x, Outside: x*h, Inside: h*x, Last: h*h)=x2+2xh+h2+10 (combine like terms (xh+xh=2xh))So if f(x)=x2+10, then f(x+h)=x2+2xh+h2+10
Apply the reciprocal rule: If f(x) = 1/h(x) then f'(x) = -h'(x)/(h(x))^2
f = 54
It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2
10 fingers in 2 hands?
h= -4
When h=10, 2h-9 = 2(10)-9 = 20-9 = 11 .
2
The pH of a solution with [H+] = 7.0 x 10^-2 is pH = -log(7.0 x 10^-2) = 1.15.
h - 4 = 10 Therefore, h = 10 + 4 h = 14
Surface Area = 2*(L*W + W*H + H*L) = 2*(7*5 + 5*2 + 2*7) = 2*(35+10+14) = 2*59 = 118 square units.
Not according to the usual definitions of "differentiable" and "continuous".Suppose that the function f is differentiable at the point x = a.Then f(a) is defined andlimit (h -> 0) [f(a+h) - f(a)]/h exists (has a finite value).If this limit exists, then it follows thatlimit (h -> 0) [f(a+h) - f(a)] exists and equals 0.Hence limit (h -> 0) f(a+h) exists and equals f(a).Therefore f is continuous at x = a.