1/3
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Integral of sqrt(2x) = integral of (2x)1/2 = √2/(3/2)*(x)3/2 + c = (2√2)/3*(x)3/2 + c where c is the constant of integration. Check: ( (2√2)/3*(2x)3/2 + c )' = (2√2)/3*(3/2)(x)(3/2)-1 + 0 = √2*(x)1/2 = √2x
6x + 9 = -3 6x/3 + 9/3 = -3/3 2x + 3 = -1 2x + 3 - 3 = -1 - 3 2x = -4 2x/2 = -4/2 x = -2
4x2-4x-3 = 0 (2x-3)(2x+1) = 0 x = 3/2 or x = -1/2
if you mean 2x-1*3 then the answer is: 2x-3
3x + 5x = 2x + 28x = 2x + 26x = 2x = (2/6) = 1/3