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25 pennies is one quarter
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Is not p and q equivalent to not p and not q?
Think of 'not' as being an inverse. Not 1 = 0. Not 0 = 1. Using boolean algebra we can look at your question. 'and' is a test. It wants to know if BOTH P and Q are the same and if they are 1 (true). If they are not the same, or they are both 0, then the result is false or 0. not P and Q is rewritten like so: (P and Q)' = X not P and not Q is rewritten like: P' and Q' = X (the apostrophe is used for not) We will construct a truth table for each and compare the output. If the output is the same, then you have found your equivalency. Otherwise, they are not equivalent. P and Q are the inputs and X is the output. P Q | X P Q | X ------ 0 0 | 1 0 0 | 1 0 1 | 1 0 1 | 0 1 0 | 1 1 0 | 0 1 1 | 0 1 1 | 0 Since the truth tables are not equal, not P and Q is not equivalent to not P and not Q. Perhaps you meant "Is NOT(P AND Q) equivalent to NOT(P) AND NOT(Q)?" NOT(P AND Q) can be thought of intuitively as "Not both P and Q." Which if you think about, you can see that it would be true if something were P but not Q, Q but not P, and neither P nor Q-- so long as they're not both true at the same time. Now, "NOT(P) AND NOT(Q)" is clearly _only_ true when BOTH P and Q are false. So there are cases where NOT(P AND Q) is true but NOT(P) AND NOT(Q) is false (an example would be True(P) and False(Q)). NOT(P AND Q) does have an equivalence however, according to De Morgan's Law. The NOT can be distributed, but in doing so we have to change the "AND" to an "OR". NOT(P AND Q) is equivalent to NOT(P) OR NOT(Q)
A trait has two alleles represented by p and q If p equals 0.19 what is q?
q is 1-p = 0.81
What does p over q mean in algebra?
P! / q!(p-q)!
If B is between P and Q?
If B is between P and Q, then: P<B<Q
What is 4 times the sum of q and p?
4(p + q), or 4p + 4q
What is the truth table for p or q and the opposite of p and q?
P . . Q . . (P or Q)0 . . 0 . . . 00 . . 1 . . . 11 . . 0 . . . 11 . . 1 . . . 1=================P . . Q . . NOT(P and Q)0 . . 0 . . . . 10 . . 1 . . . . 11 . . 0 . . . . 11 . . 1 . . . . 0
25 P is a Q?
25 percent is a quarter
What is the demand elasticity of P 100-4Q when Q 20?
The quantity, Q, demanded at price P is 100 - 4Q So Q = 25 - P/4 And therefore, the demand elasticity is -1/4 or -0.25, whatever the value of Q.
Is not p and q equivalent to not p and not q?
Think of 'not' as being an inverse. Not 1 = 0. Not 0 = 1. Using boolean algebra we can look at your question. 'and' is a test. It wants to know if BOTH P and Q are the same and if they are 1 (true). If they are not the same, or they are both 0, then the result is false or 0. not P and Q is rewritten like so: (P and Q)' = X not P and not Q is rewritten like: P' and Q' = X (the apostrophe is used for not) We will construct a truth table for each and compare the output. If the output is the same, then you have found your equivalency. Otherwise, they are not equivalent. P and Q are the inputs and X is the output. P Q | X P Q | X ------ 0 0 | 1 0 0 | 1 0 1 | 1 0 1 | 0 1 0 | 1 1 0 | 0 1 1 | 0 1 1 | 0 Since the truth tables are not equal, not P and Q is not equivalent to not P and not Q. Perhaps you meant "Is NOT(P AND Q) equivalent to NOT(P) AND NOT(Q)?" NOT(P AND Q) can be thought of intuitively as "Not both P and Q." Which if you think about, you can see that it would be true if something were P but not Q, Q but not P, and neither P nor Q-- so long as they're not both true at the same time. Now, "NOT(P) AND NOT(Q)" is clearly _only_ true when BOTH P and Q are false. So there are cases where NOT(P AND Q) is true but NOT(P) AND NOT(Q) is false (an example would be True(P) and False(Q)). NOT(P AND Q) does have an equivalence however, according to De Morgan's Law. The NOT can be distributed, but in doing so we have to change the "AND" to an "OR". NOT(P AND Q) is equivalent to NOT(P) OR NOT(Q)
Probablity of an event occurring to the probablity that it will not occor?
Let p = probability the event will occur; and q = probability the event will not occur. The relationship is p=1-q or q=1-p.
What is the proof of the modus ponens not by the truth table?
1)p->q 2)not p or q 3)p 4)not p and p or q 5)contrudiction or q 6)q
If 3 divided by p equals 6 and 3 divided by q equals 15 then p - q equals?
3/p = 6 p = 3/6 = 1/2 3/q = 15 q = 3/15 = 1/5 p - q = 1/2 - 1/5 p - q = 5/10-2/10 = 3/10
Make a truth table for the statement if p then not q?
. p . . . . . q. 0 . . . . . 1. 1 . . . . . 0
How do you find the percentage of a trait?
If you are interested in genotype as opposed to phenotype use the Hardy-Weinburg equation. q (squared) + 2qp + p (squared) = 1.0. Where q is represents the recessive allele and p is the dominant allele. If you know the number of homozygous recessive individuals in a population you can calculate for q and determine p using the equation q+p=1 If the number of recessive individuals in a population is .25 this equals q(squared) so q=.5 and p=.5 .25+.5+.25=1 This means that 50% of all the alleles for this trait are recessvie and 50% are dominant. If .36 of the population is homozygous recessive then q=.6 and p=.4 and the Hardy-Weinberg equation shows .36+2[(.6)(.4)]+.16=1=.36+.48+.16 To get percentage multiply by 100.
Difference between plus plus p and p plus plus?
++p increments p by 1 unit and returns the result. This is known as pre-increment.int p = 0;int q = ++p; // q=1, p=1.This is effectively the same as saying:int p = 0;p = p + 1; // p= 1.int q = p; // q = 1.p++ also increments p by 1 unit, but returns the previous value of p, not the current value. This is known as post-increment.int p = 0;int q = p++; // q=0, p=1.This is the same as saying:int p = 0;int q = p; // q = 0.p = p + 1; // p = 1.Of the two forms, ++p is marginally quicker because p++ employs a temporary variable for the return value, whereas ++p does not. As such, ++p is the preferred form for looping purposes:for( int p=0; p
What are rational numbers that are also integers?
All integers {..., -2, -1, 0, 1, 2, ...} are rational numbers because they can be expressed as p/q where p and q are integers. Let p equal whatever the integer is and q equal 1. Then p/q = p/1 = p where p is any integer. Thus, all integers are rational numbers.
A trait has two alleles represented by p and q If p equals 0.19 what is q?
q is 1-p = 0.81
