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What is the sum of all the factors of 48?
The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48. Their sum is 124.
Find two integers that have a product of -48 and a sum of -2?
-46
8 times the sum of 4 and 2?
8 x (4+2) = 48
Is 9.6 divided by 2 a rational number?
4.8
Determine the sum of the reciprocals of the two number which are their sum is 2 and their product is 3?
sannie
What is the sum of twice a number and 48?
Let x = 3 2x + 48 = 2(3) + 48 = 6 + 48 = 54
The sum of 2 numbers is 72. Their difference is 48. W hat are the 2 numbers?
These are easy if you work this way... 72 - 48 = 24, half of 24 is 12 which is the smaller number and 12 + 48 = 60which is the other number.
What is the sum of the first 48 odd numbers?
2304Sum of an arithmetic progression = n/2 (2a + (n-1)d) where n is the number of items, a is the first item and d is the difference between them:For the first 48 odd numbers:n = 48a = 1d = 2→ sum = 48/2 (2 x 1 + (48 - 1) x 2)= 482= 2304The sum of the first n odd numbers is always n2
What is the sum of all the common factors of 42 and 48?
It is only possible to have one even prime factor of any number - as there is only one even prime number, 2. The sum of these is therefore 2.
The sum of two whole number is 72 their difference is 48 what are the two numbers?
74 - 48 = 2424 / 2 = 12 (1st number)72 - 12 = 60 (2nd number)Check...12 + 60 = 7260 - 12 = 48
What is the sum of the interiorangles of a 48-gon?
To find the sum of the angles for any polygon just use this formula: (n-2) times 180 where n is the number of sides in the polygon. So for a 48-gon it would be : (48 - 2) times 180 46 times 180 = 8280 degrees
What is the sum of 4 plus 2 multiplied by 8?
48. 4+2=6x8=48
What 2 number are even least common multiple of 48 but the 2 number has the sum of 40?
This question makes no sense whatsoever. The world "least" is a superlative term. That means there can be only one such number. So two numbers cannot be LCMs in the same scenario. Next, the least "common" multiple (LCM) refers to a multiple that is COMMON to two or more numbers. You have only one number, 48, in the question! The least common multiple of 48 and some other number must be at least as great as 48 and so two numbers - if they could exist, would have a sum of at least 48 + 48 = 96. You need to read up on LCM
Find the sum of the first 48 terms of an aritmetic sequance 2 4 6 8?
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
What is the sum of all the factors of 48?
The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48. Their sum is 124.
What is the sum of prime numbers 2 3 11 13 19?
sum = 48
What are two factors of 48 with sum of 26?
24 and 2 2 X 24=48 2+24=26
