8 x (4+2) = 48
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If the sum of a number and 4 is (X + 4) then twice that is 2(X + 4) which is 2X + 8
3(n+2) = -8 n = -14/3 or 4 and 2/3
mn = 8 ( Product) m + n = 6 (Sum) Hence m = 6 - n Substitute (6 -n)n = 8 Multiply out the brackets 6n - n^(2) = 8 n^(2) - 6n + 8 = 0 It is now in quadratic form and will factor Hence ((n - 2)(n - 4) = 0 n = 2 & n = 4 So '2' & '4' are the two numbers. Verification 2 + 4 = 6 2 x 4 = 8
The numbers 4 and 8 (4 x 8 = 32) sum to 12. The numbers 2 and 16 (2 x 16 = 32) sum to 18. There are no other factors which are integers, so 4 and 8 is the answer.
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