If the sum of a number and 4 is (X + 4) then twice that is 2(X + 4) which is 2X + 8
3(n+2) = -8 n = -14/3 or 4 and 2/3
mn = 8 ( Product) m + n = 6 (Sum) Hence m = 6 - n Substitute (6 -n)n = 8 Multiply out the brackets 6n - n^(2) = 8 n^(2) - 6n + 8 = 0 It is now in quadratic form and will factor Hence ((n - 2)(n - 4) = 0 n = 2 & n = 4 So '2' & '4' are the two numbers. Verification 2 + 4 = 6 2 x 4 = 8
The numbers 4 and 8 (4 x 8 = 32) sum to 12. The numbers 2 and 16 (2 x 16 = 32) sum to 18. There are no other factors which are integers, so 4 and 8 is the answer.
8
the sum of 8 and 4 times a number is 36
8 x (4 + 2) = 48
Suppose the number is x. The sum of the number and two is x+2 Four times the sum is 4(x+2) The number times 8 is 8x 24 less than the number times 8 is 8x-24 4(x+2) = 8x-24 4x+8=8x-24 so 4x = 32 and x = 8
It is: 9h+4(2+h) = 9h+8+4h => 13h+8
48
It is: (5+4) times 8 = 72
It is: 3(8+4) = 36
Y = 4 (x+8)
8n + 2
The expression that represents two times the sum of p and 8 is 2(p + 8).
4*(x - 8)
2/3x(4+8)=8