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How do you factor x squared plus x minus one half?
(x^2+x-1/2)= x(x+1)-1/2 [x + (1 - square root of 3)/2][x + (1 + square root of 3)/2] = 0 Check it: x^2 + x/2 + (square root of 3)x)/2 + x/2 + 1/4 + (square root of 3)/4 - (square root of 3)x/2 - (square root of 3)/4 - 3/4 = 0 x^2 + x/2 + x/2 + [(square root of 3)x]/2 - [(square root of 3)x]/2 + (square root of 3)/4 - (square root of 3)/4 + 1/4 - 3/4 = 0 x^2 + x - 2/4 = 0 x^2 + x - 1/2 = 0 How to find this roots: Using the completing the square method: x^2 + x - 1/2 = 0 x^2 + x = 1/2 x^2 + x + 1/4 = 1/2 + 1/4 (x + 1/2)^2 = 3/4 x + 1/2 = (plus & minus)(square root of 3/4) x = -1/2 + (square root of 3)/2 x = - 1/2 - (square root of 3)/2
Which two values of x are roots of the polynomial 3x2-3x plus 1?
let f(x) = 3x^2 - 3x + 1. The roots of f is the same as asking for x where f(x) = 0. So we do it f(x) = 0, 3x^2 - 3x + 1 = 0. Using "complete the square" method 3(x^2 - x) + 1 = 0 3(x^2 + (2 . - 1/2 . x) + (-1/2)^2 -(-1/2)^2) + 1 = 0 3(x - 1/2)^2 -3/4 + 1 = 0 3(x - 1/2)^2 + 1/4 = 0 By the quadratic formula, the solution comes out to be x = [3+√(-3)]/6 and x = [3-√(-3)]/6 or x = (3+i√3)/6 and x = (3-i√3)/6 in other words, the solutions are complex numbers.
X over 2 plus 3 equals 4?
-1
What is 2 430 090 in expanded form?
2,430,090 = (2 x 106) + (4 x 105) + (3 x 104) + (0 x 103) + (0 x 102) + (9 x 101) + (0 x 100) or (2 x 1000000) + (4 x 100000) + (3 x 10000) + (0 x 1000) + (0 x 100) + (9 x 10) + (0 x 1)
X2 - x - 6?
-4
