Q: Solve x 3-2x 2 plus x-4 0?

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16x2 + 32x - 65 = 0 factorises (4x + 13)(4x - 5) This makes x either -13/4 or 5/4.

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If you mean 4x-32x-4 = 0, the answer is x= -1/7

8x2 + 16x + 8 = 0

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Isolating xx = (6+6)/32x = 0.375

16x2 + 32x - 65 = 0 factorises (4x + 13)(4x - 5) This makes x either -13/4 or 5/4.

Limx→0 [ 1 / (x - 4) + 1 / (x + 4) ] / x = Limx→0 1 / (x2 - 4x) + 1 / (x2 + 4x) = Limx→0 (x2 + 4x) / (x4 - 16x2) + (x2 - 4x) / (x4 - 16x2) = Limx→0 (x2 + 4x - 4x + x2) / (x4 - 16x2) = Limx→0 2x2 / (x4 - 16x2) = Limx→0 2 / (x2 - 16) = 2 / (0 - 16) = -1/8

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y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0

x4-8 = 0 x4 = 8 Eradicate the the power of 4 x = 1.681792831 Check: 1.6817928314 = 8.000000009 which is just about correct.

sin2x + 3*cos2x = 0sin2x = -3*cos2xtan2x = -32x = arctan(-3)x = 0.5*arctan(-3) in the domain which should have been specified. As none has, the question has no answer.

If you mean 4x-32x-4 = 0, the answer is x= -1/7

8x2 + 16x + 8 = 0

a2+30a+56=0 , solve for a Using the quadratic formula, you will find that: a=-2 , a=-28

x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.

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