3x2-4x-4=0
(3x+2)(x-2)+0
x=-3/2, 2
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It is a quadratic expression and is (3x+2)(x-2) when factored
It depends on what you wish to subtract them from. The solution is to write the minuend (what you want to subtract FROM). Then append the binomial or monomial with the sign of each term changed. Then combine like terms.For example, if you wish to subtract 3x2 - 4x + 6 from sin(x) + 5x, the solution issin(x) + 5x - 3x2 + 4x - 6 = sin(x) + x - 3x2 - 6
(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)
3x2= 6 6-(4x-2)= 6--8= 6+8 = 14 14+7 = 21
It is of the 2nd degree.