It is a quadratic expression and is (3x+2)(x-2) when factored
It depends on what you wish to subtract them from. The solution is to write the minuend (what you want to subtract FROM). Then append the binomial or monomial with the sign of each term changed. Then combine like terms.For example, if you wish to subtract 3x2 - 4x + 6 from sin(x) + 5x, the solution issin(x) + 5x - 3x2 + 4x - 6 = sin(x) + x - 3x2 - 6
(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)
3x2= 6 6-(4x-2)= 6--8= 6+8 = 14 14+7 = 21
It is of the 2nd degree.
x(3x-4)
3x2 + 4x factors to x(3x + 4)
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x + 2) - 4(x + 2) = (x + 2)(3x - 4).
(x - 4) or (x + 8)
x3 + 3x2 - 4x -12 x2(x + 3) - 4(x + 3) (x2 - 4)(x+3)
It is a quadratic expression and is (3x+2)(x-2) when factored
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x+2) - 4(x+2) = (3x-4)*(x+2)
The discriminant is -32.
no 3x2=6 then 4x-15= -60 so 6 added with - 60 = -54
3x2 + 4x + 1 = ?? This is a quadratic equation. The equation can be made to equal any number and this will determine the corresponding values of x. EXAMPLE : 3x2 + 4x + 1 = 96 (x = 5 or x = -19/3) Alternatively, if x is known then this will determine the result. EXAMPLE : If x = 2 then (3 x 4) + (4 x 2) + 1 = 12 + 8 + 1 = 21 In normal use, a quadratic equation is presented as equal to zero. In this example : 3x2 + 4x + 1 = 0
(3x+4)(x-2) 3x2 -6x+4x-8 3x2-2x-8
6x2 - 4x (6/2)x2 - (4/2)x = 3x2 - 2x ========