-4
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This is a quadratic equation question to find the value of x. x2-x-6 = 0 (x+2)(x-3) = 0 So x = -2 or +3
(x - 2)(x - 3)
x2 + 7x + 6 = (x + 6) (x + 1)
x2 + 5x - 6 can be rewritten as (x+1)(x-6). Setting each bracket = 0 gives x = -1 or x=6.
6
x2 + x = 6, therefore x2 + x - 6 = 0This can be factored : x2 + x - 6 = (x + 3)(x - 2) = 0This equation holds true when x + 3 = 0 or x - 2 = 0.When x + 3 = 0 then x = -3 : When x - 2 = 0 then x = 2