Yes because A > B, B > C, so A has to be > C.ExampleA=5B=3C=1A (5) > B (3)B (3) > C (1)A (5) > C (1)
The transitive property of equality states for any real numbers a, b, and c: If a = b and b = c, then a = c. For example, 5 = 3 + 2. 3 + 2 = 1 + 4. So, 5 = 1 + 4. Another example: a = 3. 3 = b. So, a = b.
a + b + c = 180 b = 3a c = 5a Substituting the values of b and c into the first equation. a + 3a + 5a = 180 or 9a = 180 so that a = 20 then b = 3a = 3*20 = 60 and c = 5a = 5*20 = 100
(a + b) + c = a + (b + c) the parenthesis means you are supposed to add a and b first on the left, but the property tells you it is ok to regroup and add b and c first... you will get the same answer ( 3 + 6) + 7 gives the same answer as 3 + (6 + 7)
Horse Isle Answer: No EXPLANATION: The simplest way to solve is to simply assume numbers to substitute the variables: a=1, b=5, c=13 does this match the first two conditions? yes, it does: 1
#include<stdio.h> int main() { int a,b,c,d; for(a=1; a<5; a++) { for(b=1; b<5; b++) { for(c=1; c<5; c++) { for(d=1; d<5; d++) { if(!(a==b a==c a==d b==c b==d c==d)) printf("dd\n",a,b,c,d); } } } } return 0; }
a + c - b = 3 + 2 - 5 = 5 - 5 = 0
If a = -15, b = 5 and c = -2 a - b - c = -15 - 5 - (-2) = -20 + 2 = -18
C, D ,B,A,A,C,B,C,C,B,C,D,A,D,B,B,D,B,A,C
Well, isn't that just a happy little math problem! If A is less than B and B plus C equals 10, then it must be true that A plus C is less than 10. Just remember, in the world of numbers, everything adds up beautifully in the end.
If any number B is subtracted from a number A to give C, then C+B =A If A - B = C then B+C = A Eg 7 - 2 = 5 Hence 2 + 5 = 7
Yes because A > B, B > C, so A has to be > C.ExampleA=5B=3C=1A (5) > B (3)B (3) > C (1)A (5) > C (1)
10+5c
No...C-5 is bigger than B-52
Assuming the 10 = Cup A, 4 = Cup B and 3 = Cup C 1) Fill Cup C (A=0, B=0, C=3) 2) Pour Cup C into Cup A (A=3, B=0, C=0) 3) Fill Cup B (A=3, B=4, C=0) 4) Fill Cup C from Cup A (A=3, B=1, C=3) 5) Pour the remainder of Cup B into Cup A (A=4, B=0, C=3) 6) Empty Cup C (A=4, B=0, C=0) 7) Fill Cup B (A=4, B=4, C=0) 8) Fill Cup C from Cup A (A=4, B=1, C=3) 9) Pour the remainder of Cup B into Cup A (A=5, B=0, C=3) 10) Empty Cup C (A=5, B=0, C=0) 11) Fill Cup B (A=5, B=4, C=0) 12) Fill Cup C from Cup A (A=5, B=1, C=3) 13) Empty Cup C (A=5, B=1, C=0) 13) Pour the remainder of Cup B into Cup C (A=5, B=0, C=1) 14) Fill Cup B (A=5, B=4, C=1) so assuming you count the filling of cups as pours your answer is 14
It helps to consider subtraction as the addition of the additive inverse, in this case, a - b = a + (-b), where (-b) is the additive inverse of b. In this case: (a - b) - c = (a + (-b)) + (-c) = a + (-b) + (-c) a - (b - c) = a + -(b + (-c)) = a + -(b + (-c)) = a + -b + c As you can see, the "c" part is inverted. Here is an example with numbers: (10 - 5) - 1 = 4 10 - (5 - 1) = 10 - 4 = 6 In the last subtraction, the result is that the 1 is added instead of subtracted.
This deals with ratios and proportions. ⊱ ────── ✯ ────── ⊰ A : B = 2 : 3 B : C = 4 : 5. Now, to find A : B : C, we need to make the value of B equal in A : B ratio and B : C ratio. Here, Value of B in A : B ratio is 3; and B : C ratio is 4. LCM of 3 and 4 is 12. Therefore, we multiply 4 to the first ratio and 3 to the second ratio. A : B = 2 × 4 : 3 × 4 A : B = 8 : 12 Also, B : C = 4 × 3 : 5 × 3 B : C = 12 : 15 Now, we can combine A : B and B : C. A : B : C = 8 : 12 : 15.