12 + 8r - 6 = 7r - 5 - 3 8r +6 = 7r -8 r = -14
7 × (r + 8) = 7(r + 8) = 7r + 56
I think you mean r2 -7r -8 = 0. If so, then factor it: (r+1)(r-8) = 0 Then set r+1 = 0, r+1-1=-1, r = -1 Set r-8 =0, r-8+8 = 8 so r = 8
multiply r2+7r+10/3 by 3r-30/r2-5r-50 weegy
how do i solve -3r+3r=-6(7+7r)-7(4-7r)
12 + 8r - 6 = 7r - 5 - 3 8r +6 = 7r -8 r = -14
I think so.r2 + 7r + 6 = [ (r+6) (r+1) ]
2r + 7r - 6t - r + 7t = 8r + t
7 × (r + 8) = 7(r + 8) = 7r + 56
If that's the equation 6r + 7 = 13 + 7r, r = -6
9r-1?
100 - 7r = 44 Subtract 100 from both sides: -7r = -56 Divide both sides by -7: r = 8
63
Simplified its 12r+3s
if the x in the formula means multiply (next time please use * to denote multiplication) then: 7r-38
(r + 1)(2r + 5)
I think you mean r2 -7r -8 = 0. If so, then factor it: (r+1)(r-8) = 0 Then set r+1 = 0, r+1-1=-1, r = -1 Set r-8 =0, r-8+8 = 8 so r = 8