10x2 - 64 = 36 + 6x2; whence, 4x2 - 100 = 0, x2 = 25, and x = ±5.
If that's 6x2, the answer is (2x + 1)(3x - 2)
x = 0
x = -½
56
6x2 + 9x = 0 3x(2x + 3) = 0 3x = 0 or 2x + 3 = 0 x = 0 or x = -3/2
2x(3x+6) = 0 x = 0 or x = -2
6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.
When the given expression equals 0 then x = -1/6 and x = -6
10x2 - 64 = 36 + 6x2; whence, 4x2 - 100 = 0, x2 = 25, and x = ±5.
If: 10x2-64 = 36+6x2 Then: 4x2-100 = 0 And: (2x-10)(2x+10) = 0 So: x = 5 or x = -5
15x2-56 = 88+6x2 15x2-6x2-56-88 = 0 9x2-144 = 0 Divide all terms by 9:- x2-16 = 0 (x-4)(x+4) = 0 x = 4 or x = -4
-6x2 + 3x - 4 can be factored into (-x + 4)(x + 1). This equals 0 only when x is either 4 or -1. Therefore, the latter two numbers are both roots of the given function.
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x = -1/3 or 11/2 3 = 6x2 - 7x ⇒ 6x2 - 7x - 3 = 0 ⇒ (3x + 1)(2x - 3) = 0 ⇒ (3x + 1) = 0 → x = -1/3 or (2x - 3) = 0 → x = 11/2
6x2 + 64x - 12 = 10 ∴ 6x2 + 64x - 22 = 0 ∴ 3x2 + 32x - 11 = 0 ∴ 3x2 + 33x - x - 11 = 0 ∴ 3x(x + 11) - 1(x + 11) = 0 ∴ (3x - 1)(x + 11) = 0 ∴ x ∈ {1/3, -11}
(3x + 4)(2x - 1) = 0 3x = -4 x = -4/3 2x = 1 x = 1/2 x = 1/2, -4/3