(7x + 5)(x - 2)
10 + 9x
x2-9x = x(x-9)
Asuming you ment The Factor of x^2+9x+18 the answer is (x+3)(x+6) Asuming you ment The Factor of x^2+9x+18 the answer is (x+3)(x+6)
9x+39
you can't
I suppose you mean, how do you factor it. 7x2 - 9x - 10 = (7x + 5)(x - 2).
21x2 + 27x - 30 = 3*(7x2 + 9x - 10) = 3*(7x2 - 5x + 14x - 10) =3*[x*(7x - 5) + 2*(7x - 5)] = 3*(7x - 5)*(x + 2)
7x2-9x-10 7*-10=-707x2-14x+5x-10=-70\........./.......\/7xx 2*7x...5x 2*57x(x-2)+5(x-2)=-70(x-2)(7x+5)=-70I forget how to do the rest. But I graphed it and the solution set is {-0.5,2}
With suitable signs between the terms, yes.
It is an algebraic expression of 3 terms
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
9x2 + 9x - 10 =(3x - 2)(3x + 5)
(x - 10)(x + 1)
10 + 9x
if the x in "7x2" is variable x, then 7x(2)-5x=0 14x-5x=0 9x=0 x=0 if the x in "7x2" is a symbol for multiplication, then 7(2)-5x=0 14-5x=0 -5x= -14 5x=14 x= 14/5 x= 2 4/5 or, to factor it out... x(14-5)=0 x(9)=0 9x=0
Factor 7x2 - 9x - 10 = 0.7 * -10 = -7070 = 2 * 35 = 2 * 5 * 7Factors of 70: 1,2,5,7,10,14,35,701 x 70 = 702 x 35 = 705 x 14 = 707 x 10 = 70The sum should be negative, so the larger number in the sum must be negative.product of -70 (sum of -9) :1 + (-70) = -692 + (-35) = -335 + (-14) = -97 + (-10) = -3The sums match up, so now we have the factors.(x+5)(x+(-14)) = 0(x+5)(x-14) = 0However, the x2 must have a 7 in front of it, so divide the 14 by 7.(7x+5)(x-2) = 0And, if you have extra time, you can foil it back out to make sure you did it correctly.7x2 - 14x + 5x -10 = 07x2 - 9x - 10 = 0This confirms that the factorization is correct.Finally, if you want to solve for x, just set each term equal to zero.7x+5 = 0 or x-2 = 07x = -5 or x = 2x = -5/7 or 2
(9x - 10)(x + 3)