7x2-9x-10 7*-10=-70
7x2-14x+5x-10=-70
\........./.......\/
7xx 2*7x...5x 2*5
7x(x-2)+5(x-2)=-70
(x-2)(7x+5)=-70
I forget how to do the rest. But I graphed it and the solution set is {-0.5,2}
9x2-9x-10 = (3x+2)(3x-5) when factored
(9x + 8)(9x - 8)
It is a difference of squares. 9x^2-49=(3x+7)(3x-7)
(3x + 8)(3x - 8)
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
x2-9x+8=0 has two solutions:x = 8x = 1
It is possible.
x2-9x can be factored by taking x out of each term x(x-9)
(3x - 4)(2x^2 + 6x + 5)
x2 - 9x + 18 = (x - 3)(x - 6)
(x - 9)(x^2 + 9x + 81)
(x + 12)(x - 3)