4n-8=3n+2 4n=3n+2+8 4n=3n+10 4n-3n+10 n=10 N = 10
8 = 8 times x raised to the zero, so it could be considered a zero order polynomial.Typically polynomials have multiple terms, though.
The nth term is: 4n
(((x*3)/4)+8)-5 = y --------------------------------------------------------------------------------------------------- Assume the number is Y three times the number + 8 = 3Y + 8 1/4 th this quantity is (3Y + 8)/4 then 5 less this quantity = 5 - (3Y + 8)/4 Assume Y = 4 for example then the result is zero Assume Y = 8 for example then the result is -3 Assume Y = zero then the result is +3
I am not quite sure if you are asking me to factor this or solve it. So i guess I'll do both: Factoring: x2-10x+16 x2-2x-8x+16 x(x-2)-8(x-2) (x-8)(x-2) Solving: You set this factored version of the equation to zero and solve by figurin out x-value would cause the equation to equal zero. This can be done by taking each bracket and making them equal zero, because if one of the brackets were to equal zero, then the equation would go to zero ebcause anything times zero equals zero. x-8=0 x=8 this means one of the answers is 8 x-2=0 x=2 this means the other answer is 2 So the final answer would be x=2,8
4
5
4n-8
4N + 8
8+4n=-4 algebra gives us 4n=-12 n=-3
An equation in the variable n.
4n-8=3n+2 4n=3n+2+8 4n=3n+10 4n-3n+10 n=10 N = 10
4 + 4n - 12 = 4n - 8
0.625 = 5/8
As follows:- 4n+13 = n-8 4n-n = -8-13 3n = -21 n = -7
4n/7 + 8 = 20 subtract 8 from each side: 4n/7 = 12 multiply each side by 7: 4n = 84 n = 21
Zero times anything is zero.