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Yes.

y = e^x

dy/dx = e^x

Note: e^x = 1 + x + x²/2! + x³/3! + ... + x^r/r! + ...

→ d/dx(e^x) = 1 + x + x²/2! + x³/3! + ... + x^(r-1)/(r-1)! + ...

(The font is extremely bad: r! is r-exclamation mark = r factorial = r × (r-1) × (r-2) × ... × 2 × 1)

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7y ago

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