log4(x) +16 +log4(x) +4=3
2log4(x)=-17
log4(x)=-17/2
x=4^(-17/2)
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Since the parentheses have been lost from the question,
it could easily be interpreted this way instead, (as well as
a few others):
x log(4x) + 16 + log(4x) + 4 = 3
(x + 1) log(4x) = -17
4x = 10-17/(x+1)
4x = the (x+1)th root of 10-17
Come on back and solve that one for us.
2 log(x) + 3 log(x) = 105 log(x) = 10log(x) = 10/5 = 210log(x) = (10)2x = 100
x = 3*log8 = log(83) = log(512) = 2.7093 (approx)
You calculate a log, you do not solve a log!
If log(Kf) = 5.167 then Kf = 105.167 = 146,983 (approx).
log(9x) + log(x) = 4log(10)log(9) + log(x) + log(x) = 4log(10)2log(x) = 4log(10) - log(9)log(x2) = log(104) - log(9)log(x2) = log(104/9)x2 = 104/9x = 102/3x = 33 and 1/3
log(f) + log(0.1) = 6 So log(f*0.1) = 6 so f*0.1 = 106 so f = 107
2 log(x) + 3 log(x) = 105 log(x) = 10log(x) = 10/5 = 210log(x) = (10)2x = 100
Use the identity log(ab) = log a + log b to combine the logarithms on the left side into a single term. Then take antilogarithms (just take the log away) on both sides.
The explanation and answer to the following math equation to find x -0.3 plus 5-5 log (d) equals a plus 5-5 log 4 (d) is -5 log(d)+x+4.7 = a-5 log(4 d)+5. The solution is x = a-6.63147.
x = 3*log8 = log(83) = log(512) = 2.7093 (approx)
11
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
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log(10x) = 410x = 104x = 103 = 1,000
log x + 2 = log 9 log x - log 9 = -2 log (x/9) = -2 x/9 = 10^(-2) x/9 = 1/10^2 x/9 = 1/100 x= 9/100 x=.09
You calculate a log, you do not solve a log!
If log(Kf) = 5.167 then Kf = 105.167 = 146,983 (approx).